Q2.The periodic triangular current in shown in Figure 1 has a peak value of 180 mA. Find the average power that this current delivers to a resistor. etc. - Ty2 – T/4 T/4 T)2 3T/4 /T

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A: The explanation is as follows.

Q: For the waveform of Figure, determinea) Period  I got 100us b) Frequency  I got 10kHz c)…

A: a) Given time = 525usNumber of cycles for 525us =  5 cycle + 1/4 cycle = 5.25 cycle.So period =…

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A: Given:  Im=100 A, f=25 Hz,i=100sin2πft,i=100sin50πt.

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Q: What is the peak voltage across R2? b) What is the RMS value of I1?

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Q: Find Reg between points a and b. 3.6 k2 1.8 k2 1.8 kN 10.8 k2 21.6 k2 36 kN 36 kN 9 kN 36 kN

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Q: For the waveform of Figure, determinea) Period  I got 95.45usb) Frequency  I got 10.476kHzc)…

A: a) Time for 5 cycle + 1/4 cycle is 525us5 cycle + 1/4 cycle = 5.25 cycleSo period = 525/5.25 = 100us…

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Q: The current through a 15kohm resistor is given below, using Ohm’s Law to find the voltage, convert…

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Q: Q2) Consider the circuit in Figure (3), and answer 3 branch only. a) What type of circuit is this?…

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Coulomb’s Law

Coulomb's law states that the attraction or repulsion force between two charged things is proportional to the product of their charges and inversely proportional to the square of their distance. It has an effect along the line that connects the two-point charges.