In the figure below if hy 3 m h=28 m q=500 kN/m? -1- KNim (net stress increase) HAVAVAVI. Sand 1.5 m y= 15.7 kNim Groundwater Table BxL= 1.5 mx 3.0 m him Sand Ya= 16.5 kNim Clay Yu 16 kN/m 0.68 C, =0.25 c, -0.06 h2 Please fill in the blank with only one digit and no units like this 1234 A) if the drainage in the clay layer is single drainage, resulted in 90% primary consolidation in 1 5540

In the figure below if hy 3 m h=28 m q=500 kN/m? -1- KNim (net stress increase) HAVAVAVI. Sand 1.5 m y= 15.7 kNim Groundwater Table BxL= 1.5 mx 3.0 m him Sand Ya= 16.5 kNim Clay Yu 16 kN/m 0.68 C, =0.25 c, -0.06 h2 Please fill in the blank with only one digit and no units like this 1234 A) if the drainage in the clay layer is single drainage, resulted in 90% primary consolidation in 1 5540

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

or the soil profile shown in the Figure: a. Calculate the effective stress at point C. b. How high should the water table rise so that the effective stress at C is 200 kN/m²? Dry sand Yory-165 AN 6m Groundwater table Saturated sand 13m 7-19.25 AN Dry sand Satted sand Clay
A soil profile is shown in the figure below. If a foundation load Ao=1000 lb/ft² is applied, estimate the primary consolidation settlement of the clay layer. The preconsolidation pressure oc'=2600 lb/ft² and C, =÷Cc. Use the Skempton equation to estimate the 6. compression index. Ao =110 lb/ft³ Y dry V Ground water table Sand Y=1:15 lb/ft sat Y-120 lb/ft³ sat Le=0.9 | Clay| LL=50 - - - Sand 17 ft.- 15 ft.- ft.-
Dry Sand H, Groundwater Table Clay Refer to the soil profile shown. Given H1 = 8.85 m., and H2 4.01 m If the ground water table rises by 2.19 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer Properties of dry sand Gs = 2.51, e = 0.65 Properties of clay. Gs = 2.72, e = 0.84. Round off to two decimal places. Activate Windows Go to Settings to activate Windows. < Question 18 of 20 2 A Moving to another question will save this response. ASUS C8O CD 80 5n E R- T Y H]
(1) A well is drilling to the depth of 6000 m. Formation pore pressure can be expressed in equivalent mud weight is 1.50 g/cm' at the depth and changes in proportion to well depth. Also, overburden pressure gradient is 0.0245 MPa/m. Calculate: a. Pore pressure gradient at 6000 m, MPa/m. b.Pore pressure, psi, at 6000 m. c. Matrix stress gradient, MPa/m d.Matrix stress at 6000 m, MPa
Given the soil profile below, estimate the consolidation coefficient of the clay if Ao_z = 500 psf at the middle of the clay. Use one layer for the clay in your calculation. он 10 ft 20 ft וד Incompressible Sand' V Clay sat = 120 pct CR = 0.3 TIT RR = 0.15 Pp = 1776 pst 8 Sat 120 pct
Refer to Figure 2, estimate the primary consolidation settlement in the clay layer. Given: Ag = 85 kN/m²; Hi = 2 m; H2 = 4 m; and H3= 6 m. Soil characteristics are as follows: Sand: ydx 14 kN/m³, Ysat 18 kN/m³ Clay: LL = 54; e = 0.98; Ysat 19 kN/m'; Cs =- Cc 150 kN/m? H3 Sand Clay ョ→
Figure Q1(c) shows the soil profile with groundwater table is 6 m from thesurface impermeable layer. Calculate the total stress, pore water pressureand effectives tress at points D.
7.14 For a normally consolidated clay, the following values are given: Void ratio, e k (cm/sec) 0.95 0.2 x 10-6 0.91 x 10-6 1.6 Estimate k at a void ratio of 1.1. Use Eq. (7.38). Ⓒ Cengage Learning 2014
2.2 A consolidated-drained triaxial test was conducted on a normally consolidated clay. The results are: 03=140 kN/m? (Aga) f=104KN/m2 Please determine oi and 3.
1. A soil profile is shown in Figure below. Calculate the total stress, pore water pressure, and effective stress at points A and D. Dry sand G.-2.68 *»0.6 2 m 2m Groundwater table Clay G₁-2.72 e-09
Refer to Figure below. Estimate the primary consolidation settlement in the clay layer. Given: Δσ = 150 kN/m2; H1 = 3 m; H2 = 4 m; and H3= 5 m. Soil characteristics are as follows: • Sand: γdry = 15 kN/m3, γsat = 19 kN/m3 • Clay: LL = 65; e = 0.65; γsat = 18 kN/m3; ; Cs =1/6cc σʹc = 200 kN/m2
Borings indicate that at a Queens, NY site, the top 6 meters is a loose 2) , sand with a groundwater level at 3 meters below the ground surface. Below the sand is a 10 meter thick soft clay stratum. Assume sand unit weights are ymoist = 14 kN/cubic meter and ysat = 15 kN/cubic meter. Assume clay ysat = 19 kN/cubic meter. Calculate total, pore and effective stresses at 3, 12 and 16 meters deep.