Given the following consolidation test, plot the e-log p relationship and determine if the clay layer in the field is normally consolidated or overconsolidated soil. Plot the field consolidation relationship, and determine the consolidation settlement of the clay layer due to the addition of distributed stress = 90 kPa Pressure (kPa) AH (mm) de AP 90 kPa 0.891 Yume- 15 AN 3m W. 54 0.253 0.025 0.866 107 0.507 0.050 0.841 Sand 5m 214 0.892 0.089 0.802 Clay Y- 173 KNim 429 1.551 0.154 0.737 20 m 858 2.392 0.238 0.653 1716 3.324 0.331 0.560 3432 4.263 0.424 0.467 100 3.520 0.350 0.541
Given the following consolidation test, plot the e-log p relationship and determine if the clay layer in the field is normally consolidated or overconsolidated soil. Plot the field consolidation relationship, and determine the consolidation settlement of the clay layer due to the addition of distributed stress = 90 kPa Pressure (kPa) AH (mm) de AP 90 kPa 0.891 Yume- 15 AN 3m W. 54 0.253 0.025 0.866 107 0.507 0.050 0.841 Sand 5m 214 0.892 0.089 0.802 Clay Y- 173 KNim 429 1.551 0.154 0.737 20 m 858 2.392 0.238 0.653 1716 3.324 0.331 0.560 3432 4.263 0.424 0.467 100 3.520 0.350 0.541
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Geotechnical
Transcribed Image Text:Given the following consolidation test, plot the e-log p relationship and determine if the clay layer in the field is normally consolidated or overconsolidated soil. Plot the field consolidation relationship, and determine the consolidation settlement of the clay layer due to the addition of distributed stress = 90 kPa.
**Table:**
| Pressure (kPa) | ΔH (mm) | Δe | e |
|----------------|---------|-----|------|
| 0 | 0 | 0 | 0.891|
| 54 | 0.253 | 0.025| 0.866|
| 107 | 0.507 | 0.050| 0.841|
| 214 | 1.015 | 0.089| 0.802|
| 429 | 1.551 | 0.154| 0.737|
| 858 | 2.392 | 0.238| 0.653|
| 1716 | 3.324 | 0.331| 0.560|
| 3432 | 3.520 | 0.424| 0.541|
**Diagram Explanation:**
- The diagram shows a cross-section of soil layers and stress distribution.
- The top layer is sand, 3 m thick, with a unit weight of 15 kN/m³.
- Below the sand layer is clay, 5 m thick, with a unit weight of 17.3 kN/m³.
- There is an indication of groundwater (W.T.) in the sand layer.
- The clay layer is 20 m thick overall.
- The diagram also shows an additional distributed stress of 90 kPa being applied.
- Initial void ratio of the clay, \( e_0 = 0.891 \).
- G.S. indicates ground surface.
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