In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude Fape = 1.15 N. The friction between the bar and rails is negligible. The resistance R = 8.00 0, the bar is moving at a constant speed of 2.15 m/s, the distance between the rails is e, and a uniform magnetic field B is directed into the page. (a) What is the current through the resistor (in A)? A (b) If the magnitude of the magnetic field is 2.80 T, what is the length e (in m)? m (c) What is the rate at which energy delivered to the resistor (in w)? w (d) What is the mechanical power delivered by the applied constant force (in w)? w What If? Suppose the magnetic field has an initial value of 2.80 T at time t= 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x - 0.100 m to the right of the resistor at t= 0, and again moves at a constant speed of 2.15 m/s. Derive time-varying expressions for the following quantities. (e) the current through the 8.00 0 resistor R (Use the following as necessary: t. Assume 1(t) is in A and t is in s. Do not include units in your answer.) I(e) =| A (f) the magnitude of the applied force Fapp required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fapp(t) is in N and t is in s. Do not include units in your answer.) Fap(e) =| N
In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude Fape = 1.15 N. The friction between the bar and rails is negligible. The resistance R = 8.00 0, the bar is moving at a constant speed of 2.15 m/s, the distance between the rails is e, and a uniform magnetic field B is directed into the page. (a) What is the current through the resistor (in A)? A (b) If the magnitude of the magnetic field is 2.80 T, what is the length e (in m)? m (c) What is the rate at which energy delivered to the resistor (in w)? w (d) What is the mechanical power delivered by the applied constant force (in w)? w What If? Suppose the magnetic field has an initial value of 2.80 T at time t= 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x - 0.100 m to the right of the resistor at t= 0, and again moves at a constant speed of 2.15 m/s. Derive time-varying expressions for the following quantities. (e) the current through the 8.00 0 resistor R (Use the following as necessary: t. Assume 1(t) is in A and t is in s. Do not include units in your answer.) I(e) =| A (f) the magnitude of the applied force Fapp required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fapp(t) is in N and t is in s. Do not include units in your answer.) Fap(e) =| N
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude Fnn = 1.15 N. The friction between the bar and rails is negligible. The resistance R = 8.00 n, the bar is
moving at a constant speed of 2.15 m/s, the distance between the rails is l, and a uniform magnetic field B is directed into the page.
"app
(a) What is the current through the resistor (in A)?
A
(b) If the magnitude of the magnetic field is 2.80 T, what is the length e (in m)?
(c) What is the rate at which energy is delivered to the resistor (in W)?
w
(d) What is the mechanical power delivered by the applied constant force (in W)?
w
What If? Suppose the magnetic field has an initial value of 2.80 T at time t = 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x, = 0.100 m to the right of the resistor at t = 0, and again moves at a constant speed of 2.15 m/s. Derive
time-varying expressions for the following quantities.
(e) the current through the 8.00 0 resistor R (Use the following as necessary: t. Assume I(t) is in A and t is in s. Do not include units in your answer.)
I(t) =
A
(f) the magnitude of the applied force Fann required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fann(t) is in N and t is in s. Do not include units in your answer.)
Fapp(t) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8edd889e-338a-4275-872c-5b2b400b4e22%2Faa81cbb8-5129-4e91-83c4-978512049f11%2F9cd1htq_processed.png&w=3840&q=75)
Transcribed Image Text:In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude Fnn = 1.15 N. The friction between the bar and rails is negligible. The resistance R = 8.00 n, the bar is
moving at a constant speed of 2.15 m/s, the distance between the rails is l, and a uniform magnetic field B is directed into the page.
"app
(a) What is the current through the resistor (in A)?
A
(b) If the magnitude of the magnetic field is 2.80 T, what is the length e (in m)?
(c) What is the rate at which energy is delivered to the resistor (in W)?
w
(d) What is the mechanical power delivered by the applied constant force (in W)?
w
What If? Suppose the magnetic field has an initial value of 2.80 T at time t = 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x, = 0.100 m to the right of the resistor at t = 0, and again moves at a constant speed of 2.15 m/s. Derive
time-varying expressions for the following quantities.
(e) the current through the 8.00 0 resistor R (Use the following as necessary: t. Assume I(t) is in A and t is in s. Do not include units in your answer.)
I(t) =
A
(f) the magnitude of the applied force Fann required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fann(t) is in N and t is in s. Do not include units in your answer.)
Fapp(t) =
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