A metal bar is sliding on two metal rails with constant speed v = 0.40 m/s, as shown below. The rails are separated by 0.50 m and located in a uniform magnetic field B = 0.060 T whose direction is indicated by crosses. The rails are connected by a resistor R = 2.0 N. The resistance of rails and the bar is negligible. The current flowing through the resistor is: B A rod moving with velocity v in a uniform magnetic field. О а. 0.020 А O b. 0.040 A O . 0.0060 A O d. 0.0040 A O e. 0.12 A

icon
Related questions
Question
A metal bar is sliding on two metal rails with constant speed v = 0.40 m/s, as shown below. The
rails are separated by 0.50 m and located in a uniform magnetic field B = 0.060 T whose
direction is indicated by crosses. The rails are connected by a resistor R = 2.0 . The resistance
of rails and the bar is negligible. The current flowing through the resistor is:
x x x x! ×
A rod moving with velocity v in
a uniform magnetic field.
O a.
0.020 A
O b. 0.040 A
0.0060 A
O d. 0.0040 A
Oe.
0.12 A
Transcribed Image Text:A metal bar is sliding on two metal rails with constant speed v = 0.40 m/s, as shown below. The rails are separated by 0.50 m and located in a uniform magnetic field B = 0.060 T whose direction is indicated by crosses. The rails are connected by a resistor R = 2.0 . The resistance of rails and the bar is negligible. The current flowing through the resistor is: x x x x! × A rod moving with velocity v in a uniform magnetic field. O a. 0.020 A O b. 0.040 A 0.0060 A O d. 0.0040 A Oe. 0.12 A
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions