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In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude Fapp 1.25 N. The friction between the bar and rails is negligible. The resistance R 8.000, the bar is moving at a constant speed of 2.25 m/s, the distance between the rails is , and a uniform magnetic field B is directed into the page. (a) What is the current through the resistor (in A)? 0.5929 (b) If the magnitude of the magnetic field is 2.60 T, what is the length (in m)? 0.81 (c) What is the rate at which energy is delivered to the resistor (in W)? 2.812 ✔ W (d) What is the mechanical power delivered by the applied constant force (in W)? W What If? Suppose the magnetic field has an initial value of 2.60 T at time t= 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x 0.100 m to the right of the resistor at t=0, and again moves at a constant speed of 2.25 m/s. Derive time- varying expressions for the following quantities. (e) the current through the 8.000 resistor R (Use the following as necessary: t. Assume I(t) is in A and t is in s. Do not include units in your answer.) I(t) = (f) the magnitude of the applied force Fapp required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fapp(t) is in N and t is in s. Do not include units in your answer.) Fapp(t)- - N

In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude Fapp 1.25 N. The friction between the bar and rails is negligible. The resistance R 8.000, the bar is moving at a constant speed of 2.25 m/s, the distance between the rails is , and a uniform magnetic field B is directed into the page. (a) What is the current through the resistor (in A)? 0.5929 (b) If the magnitude of the magnetic field is 2.60 T, what is the length (in m)? 0.81 (c) What is the rate at which energy is delivered to the resistor (in W)? 2.812 ✔ W (d) What is the mechanical power delivered by the applied constant force (in W)? W What If? Suppose the magnetic field has an initial value of 2.60 T at time t= 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x 0.100 m to the right of the resistor at t=0, and again moves at a constant speed of 2.25 m/s. Derive time- varying expressions for the following quantities. (e) the current through the 8.000 resistor R (Use the following as necessary: t. Assume I(t) is in A and t is in s. Do not include units in your answer.) I(t) = (f) the magnitude of the applied force Fapp required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fapp(t) is in N and t is in s. Do not include units in your answer.) Fapp(t)- - N

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude F = 1.25 N. The friction between the bar and rails is negligible. The resistance R = 8.00 02, the bar is moving at a app constant speed of 2.25 m/s, the distance between the rails is e, and a uniform magnetic field B is directed into the page. R i (a) What is the current through the resistor (in A)? 0.5929 A Fapp (b) If the magnitude of the magnetic field is 2.60 T, what is the length / (in m)? 0.81 m (c) What is the rate at which energy is delivered to the resistor (in W)? 2.812 ✓ W (d) What is the mechanical power delivered by the applied constant force (in W)? W What If? Suppose the magnetic field has an initial value of 2.60 T at time t = 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x = 0.100 m to the right of the resistor at t = 0, and again moves at a constant speed of 2.25 m/s. Derive time- varying expressions for the following quantities. (e) the current through the 8.00 resistor R (Use the following as necessary: t. Assume I(t) is in A and t is in s. Do not include units in your answer.) I(t) = A = (f) the magnitude of the applied force Fapp required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fapp(t) is in N and t is in s. Do not include units in your answer.) Fapp(t) N
Transcribed Image Text:In the figure below, an iron bar sitting on two parallel copper rails, connected to each other by a resistor, is pulled to the right with a constant force of magnitude F = 1.25 N. The friction between the bar and rails is negligible. The resistance R = 8.00 02, the bar is moving at a app constant speed of 2.25 m/s, the distance between the rails is e, and a uniform magnetic field B is directed into the page. R i (a) What is the current through the resistor (in A)? 0.5929 A Fapp (b) If the magnitude of the magnetic field is 2.60 T, what is the length / (in m)? 0.81 m (c) What is the rate at which energy is delivered to the resistor (in W)? 2.812 ✓ W (d) What is the mechanical power delivered by the applied constant force (in W)? W What If? Suppose the magnetic field has an initial value of 2.60 T at time t = 0 and increases at a constant rate of 0.500 T/s. The bar starts at an initial position x = 0.100 m to the right of the resistor at t = 0, and again moves at a constant speed of 2.25 m/s. Derive time- varying expressions for the following quantities. (e) the current through the 8.00 resistor R (Use the following as necessary: t. Assume I(t) is in A and t is in s. Do not include units in your answer.) I(t) = A = (f) the magnitude of the applied force Fapp required to keep the bar moving at a constant speed (Use the following as necessary: t. Assume Fapp(t) is in N and t is in s. Do not include units in your answer.) Fapp(t) N
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