In the figure, an electron accelerated from rest through potential difference V₁-0.910 kV enters the gap between two parallel plates having separation d = 27.9 mm and potential difference V2 63.0 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Number (i i+ i + k) Units
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- In the figure, an electron accelerated from rest through potential difference V1-1.26 kV enters the gap between two parallel plates having separation d = 19.6 mm and potential difference V2- 52.4 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Number ( o ĵ+ i R) Units mT 124.7As shown in the figure, an electron is fired with a speed of 3.43 x 106 m/s through a hole in one of the two parallel plates and into the region between the plates separated by a distance of 0.20 m. There is a magnetic field in the region between the plates and, as shown, it is directed into the plane of the page (perpendicular to the velocity of the electron). Determine the magnitude of the magnetic field so that the electron just misses colliding with the opposite plate. electronIn the figure, an electron accelerated from rest through potential difference V₁-1.03 kV enters the gap between two parallel plates having separation d-17.2 mm and potential difference V₂-108 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit- vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Number (0 7+0 3.30e-4 A) Units mT
- AS0.0-g metal ball having net charge Q = 5.50 µC is thrown out of a window horizontally north at a speed v = 22.0 m/s. The window is at a height h = 18.0 m above the ground. A uniform, horizontal magnetic field of magnitude B = 0.0100 T is perpendicular to the plane of the ball's trajectory and directed toward the west. (a) Assuming the ball follows the same trajectory as it would in the absence of the magnetic field, find the magnetic force acting on the ball just before it hits the ground. (Let the +x-direction be toward the north, the +y-direction be up and the +z-direction be east.) B. (b) Based on the result of part (a), is it justified for three-significant-digit precision to assume the trajectory is unaffected by the magnetic fleld? O Yes O No Explain.An electron in the beam of a cathod-ray tube is accelerated by a potential difference of 2.14 kV . Then it passes through a region of transverse magnetic field, where it moves in a circular arc with a radius of 0.190 m . What is the magnitude of the field?An electron initially at rest is accelerated through a potential difference of 3 kV in the positive x- direction. It enters a region where a uniform magnetic field of 5.0-mT is in a positive y-direction (perpendicular to the velocity of the electron). Calculate the radius of the path this electron will follow in the magnetic field. (e = 1.60 × 10-19 c, m electron = 9.11 × 10¯31 kg)
- An electron that has velocity т i = (2.0 x 106)i+ (3.0 × 106 10", %3D moves through the uniform magnetic field B = (0.030 T)î – (0.15T)f. (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity.An electron is accelerated through 2500 V from rest and then enters a region where there is a uniform 1.60 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron?