An electron that has velocityтi = (2.0 x 106)i+ (3.0 × 10610",%3Dmoves through the uniform magnetic field B = (0.030 T)î – (0.15T)f. (a) Find the forceon the electron due to the magnetic field. (b) Repeat your calculation for a proton havingthe same velocity.

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An electron that has velocity m m 3 = (2.0 x 106) + (3.0 x 106) moves through the uniform magnetic field B = (0.030 T)î – (0.157)I. (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity. %3D

An electron that has velocity m m 3 = (2.0 x 106) + (3.0 x 106) moves through the uniform magnetic field B = (0.030 T)î – (0.157)I. (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity. %3D

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

An electron that has velocity
т
i = (2.0 x 106)i+ (3.0 × 106
10",
%3D
moves through the uniform magnetic field B = (0.030 T)î – (0.15T)f. (a) Find the force
on the electron due to the magnetic field. (b) Repeat your calculation for a proton having
the same velocity.

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