Calculate the ratio e/m for the electron.When an electron of mass m accelerates through a potential difference ofV volts it gains kinetic energy that is equal to eV. Derive an expression for thespeed of the electron v that accelerates from rest through a voltage of V volts.(Equate kinetic energy and eV and solve for velocity)In our experiment, the electron travels in a circular path of radius r in a uniformmagnetic field B.What is the magnitude of the force on the electron? Express youranswer in terms of m, r, and v (Recall centripetal force fromThe force in (a) is provided by a magnetic field. What is themagnitude of the magnetic force experience by the electronEquate two forces you found in (a) and (b). Find the expression forV/r. Express your answer in terms of B and v only using an expression youwrote in Q 2.Finally, plug the values of v from Q2 and express V/r in terms of B,v, e, and m and show that x vvIf you plot VIr vs. VV, what does the slope of the curve give? Supposethe curve has a slope of C, find the expression for e/m that contains C and B.

Calculate the ratio e/m for the electron. When an electron of mass m accelerates through a potential difference of V volts it gains kinetic energy that is equal to eV. Derive an expression for the speed of the electron v that accelerates from rest through a voltage of V volts. (Equate kinetic energy and eV and solve for velocity) In our experiment, the electron travels in a circular path of radius r in a uniform magnetic field B.

Calculate the ratio e/m for the electron. When an electron of mass m accelerates through a potential difference of V volts it gains kinetic energy that is equal to eV. Derive an expression for the speed of the electron v that accelerates from rest through a voltage of V volts. (Equate kinetic energy and eV and solve for velocity) In our experiment, the electron travels in a circular path of radius r in a uniform magnetic field B.