In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.60 s later, at distance d = 26.0 m from the building and at angle = 67.0° with the horizontal. (a) Find h. (Hint: One way is to reverse the motion, as if on videotape.) What are the (b) magnitude and (c) angle relative to the horizontal of the velocity at which the ball is thrown (positive angle for above horizontal, negative for below)?
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- A remote-controlled car is moving around in a level (horizontal) parking lot. The velocity of the car as a function of time is given by: 3 = [5.0m/s – (0.018m/s³)t²]î + [2.0m/s + (0.55m/s²)t]j where î and ĵ are unit vectors representing two perpendicular directions on the horizontal ground (think of them as the East and North directions, if that helps you). b). What are the magnitude and direction of the car's velocity at t = 8.0 s? c). What are the magnitude and direction of the car's acceleration at t = 8.0 s? (Don't be intimated by the velocity function! Look at the î and ĵ components, and work each component separately to begin with, before combining components together to get any resultant vectors, if needed.)Problem 3: An arrow is shot from a height of 1.8 m toward a cliff of height H. It is shot with a velocity of 35 m/s at an angle of 60° above the horizontal. It lands on the top edge of the cliff 3.7 s later. What is the height H of the cliff in m? H = cos() asin() sin() tan() 7 8 9 HOME cotan() acos() 5 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() + END ODegrees O Radians vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! What is the maximum height reached by the arrow along its trajectory in meters? What is the arrow's speed just before hitting the cliff in m/s?A person stands at the edge of a cliff and throws a rock horizontally over the edge with a speed of Vo = 22.0 m/s. The rock leaves his hand at a height of h = 46.0 m above level ground at the bottom of the cliff, as shown in the figure. Note the coordinate system in the figure, where the origin is at the bottom of the cliff, directly below where the rock leaves the hand. = i (a) What are the coordinates of the initial position of the rock? (Enter your answers in m.) хо Yo = Voy Vy y = 4o (b) What are the components of the initial velocity? (Enter your answers in m/s.) Vox m/s m/s 11 m m (c) Write the equations for the x- and y-components of the velocity of the rock with time. (Use the following as necessary: t. Assume that vx and v, are in m/s and t is in seconds. Do not include units in your answers.) oral m/s m/s Simuna wir + Accumo that y andy are in meters and it is in seconds. Do not
- Consider a projectile being launched with an initial speed of 43 m/s at a variety of initial angles. Refer to the figure. What is the range, in meters, of the projectile if it is launched at an angle of θ1 = 79.7°? What is the range, in meters, of the projectile if it is launched at an angle of θ2 = 40.5°? What is the range, in meters, of the projectile if it is launched at an angle of θ3 = 90 − 79.7°, the complement of θ1?This problem will involve deriving a formula or two for a projectile launched from one height and angle and landing at a different height on Earth. Begin with a projectile launched at angle 0 above horizontal from a height y₁ with initial velocity Vo. The projectile lands at a point with height y₂. These are the given quantities: vo, 0, y₁, y2 and g. Construct formulae for each of the following, as. a function of given quantities the horizontal distance traveled. the maximum height reached. the time taken. the angle of impact. (find the final velocity components first).Asap
- To start an avalanche on a mountain, an artillery shell is fired from 1250 m from the base of the mountain at 300 m/s, 55.0°. What are its coordinates 9.0 seconds later? Where does it hit on the mountain? If you are unable to answer, draw a diagram showing why.Determine the vector magnitudes and directions for the relative velocities VA/B and VB/A, given these magnitudes and directions for the vectors VA and VB:(a) VA: magnitude 70km/h ; direction 30°VB: magnitude 50km/h ; direction 125° (b)VA: magnitude 70km/h ; direction 30°VB: magnitude 50km/h ; direction 225° (c) VA: magnitude 70km/h ; direction 30°VB: magnitude 50km/h ; direction 340° (d)VA: magnitude 70km/h ; direction 135°VB: magnitude 50km/h ; direction 60°NOTE: The direction is the angle (degrees) from the positive horizontal axes in an anticlockwise direction.In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.50 s later, at distance d = 26.0 m from the building and at angle e = 62.0° with the horizontal. (a) Find h. (Hint: One way is to reverse the motion, as if on videotape.) What are the (b) magnitude and (c) angle relative to the horizontal of the velocity at which the ball is thrown (positive angle for above horizontal, negative for below)? (a) Number Units (b) Number Units (c) Number Units
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