A ball is thrown upward, with an initial velocity of 35 meters per second, at an angle of 59° with respect to the horizontal. The ball is thrown from a height of 5 meters off the ground. The horizontal distance x from the starting point and the height y above the ground of the ball t seconds after it is thrown are given by the parametric equations below. x=(vo cose)t y=-4.91²+(v sine)t+h Here is the initial velocity, is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) When does the ball reach its maximum height? Do not round any intermediate computations. Round your answer to the nearest hundredth. 6.12 seconds (b) What is the maximum height of the ball? Round your answer to the nearest tenth. 51 meters

Q: This second answer is still incorrect.  Would there be another way to figure this out?   Thanks

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Relative Velocity

It is a measurement of an object with regards to the other object which is moving or stable or stationary. For example, if we are traveling in a bus and the bus is moving at speed of 50km/hr, then our speed is according to the nearby passenger on the bus is zero. According to them, we are not moving. But if one person standing on the ground or road observes us from outside of the bus, according to him we are moving at a speed of 50km/hr and the bus is also moving at a speed of 50km/hr. Now, the motion is recognized by the observer, it depends on a frame of reference or observer. This is motion called relative motion.