I was given wrong answer, pls help **Consider the waveform expression**\[ y(x,t) = y_m \sin (3.38 + 0.163x + 207t) \]The transverse displacement ($y$) of a wave is given as a function of position ($x$ in meters) and time ($t$ in seconds) by the above expression.### TaskDetermine the wavelength ($\lambda$), frequency ($f$), period ($T$), and phase constant ($\phi_0$) of this waveform.### Provided Answers and FeedbackThe student has provided the following answers, but they are marked as incorrect.- **Wavelength ($\lambda$)**: \[ 45.548 \times 10^5 \text{ meters} \]- **Frequency ($f$)**: \[ 65.8636 \text{ Hz} \]- **Period ($T$)**: \[ 0.01518 \text{ seconds} \]- **Phase constant ($\phi_0$)**: \[ 3.38 \]These answers are marked incorrect.### Explanation from Feedback**One way to write the general expression for a traveling wave is**:\[ y = y_m \sin (kx \pm \omega t + \phi_0) \]The order of the terms is unimportant, but:- The wavenumber ($k$) is always the coefficient of the position ($x$).- The angular frequency ($\omega$) is always the coefficient of the time ($t$).**How are $k$ and $\omega$ related to the wavelength, frequency, and period?**- **Wavenumber ($k$)**: \[ k = \frac{2\pi}{\lambda} \]- **Angular frequency ($\omega$)**: \[ \omega = 2\pi f \]### Clarifying the Values from the Waveform Equation:Given the waveform $y(x,t) = y_m \sin (3.38 + 0.163x + 207t)$:- **Wavenumber ($k$)**: \[ k = 0.163 \text{ m}^{-1

Given data: y(x ,t)= ym sin(3.38+0.163x+207t)

Consider the waveform expression. < Feedback y (x, t) = ymsin (3.38 + 0.163x + 207t) One way to write the general expression for a traveling wave is The transverse displacement (y) of a wave is given as a function of position (x in meters) and time (t in seconds) by th expression. Determine the wavelength, frequency, period, and phase constant of this waveform. y = ymsin (kx ± ot + 4o) The order of the terms is unimportant, but the wavenumber (k) is always the meters f = coefficient of the position (x) and the 45.548 ×105 65.8636 angular frequency (@) is always the Incorrect coefficient of the time (t). Incorrect How are k and o related to the T = seconds Po = wavelength, frequency, and period? 0.01518 3.38 What is the phase constant? Incorrect

Consider the waveform expression. < Feedback y (x, t) = ymsin (3.38 + 0.163x + 207t) One way to write the general expression for a traveling wave is The transverse displacement (y) of a wave is given as a function of position (x in meters) and time (t in seconds) by th expression. Determine the wavelength, frequency, period, and phase constant of this waveform. y = ymsin (kx ± ot + 4o) The order of the terms is unimportant, but the wavenumber (k) is always the meters f = coefficient of the position (x) and the 45.548 ×105 65.8636 angular frequency (@) is always the Incorrect coefficient of the time (t). Incorrect How are k and o related to the T = seconds Po = wavelength, frequency, and period? 0.01518 3.38 What is the phase constant? Incorrect

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

I was given wrong answer, pls help

**Consider the waveform expression**

\[ y(x,t) = y_m \sin (3.38 + 0.163x + 207t) \]

The transverse displacement ($y$) of a wave is given as a function of position ($x$ in meters) and time ($t$ in seconds) by the above expression.

### Task
Determine the wavelength ($\lambda$), frequency ($f$), period ($T$), and phase constant ($\phi_0$) of this waveform.

### Provided Answers and Feedback
The student has provided the following answers, but they are marked as incorrect.

- **Wavelength ($\lambda$)**:
\[
45.548 \times 10^5 \text{ meters}
\]

- **Frequency ($f$)**:
\[
65.8636 \text{ Hz}
\]

- **Period ($T$)**:
\[
0.01518 \text{ seconds}
\]

- **Phase constant ($\phi_0$)**:
\[
3.38
\]

These answers are marked incorrect.

### Explanation from Feedback
**One way to write the general expression for a traveling wave is**:
\[ y = y_m \sin (kx \pm \omega t + \phi_0) \]

The order of the terms is unimportant, but:
- The wavenumber ($k$) is always the coefficient of the position ($x$).
- The angular frequency ($\omega$) is always the coefficient of the time ($t$).

**How are $k$ and $\omega$ related to the wavelength, frequency, and period?**
- **Wavenumber ($k$)**:
\[
k = \frac{2\pi}{\lambda}
\]

- **Angular frequency ($\omega$)**:
\[
\omega = 2\pi f
\]

### Clarifying the Values from the Waveform Equation:
Given the waveform $y(x,t) = y_m \sin (3.38 + 0.163x + 207t)$:

- **Wavenumber ($k$)**:
\[
k = 0.163 \text{ m}^{-1

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