In the E₁cB Mechanism of Elimination, The ß-Carbon Is Deprotonated First, ToGive The "Conjugate Base" Of The SubstrateE1cB, Step 1:MHH3CBH3CHaLGa = alpha carbon (attachedto LG)ß = beta carbon (attachedto H)B-HMH3CBH3CSHaLGconjugatebaseLG = leaving group (e.g. Br)Bonds BondsFormed BrokenCB-HB-H

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In the E₁cB Mechanism of Elimination, The B-Carbon Is Deprotonated First, To Give The "Conjugate Base" Of The Substrate E1cB, Step 1: M H H3C H SH H3C LG alpha carbon (attached to LG) ß = beta carbon (attached to H) B-H M H H₂C B H3C LG conjugate base LG leaving group (e.g. Br) Bonds Bonds Formed Broken CB-H B-H

In the E₁cB Mechanism of Elimination, The B-Carbon Is Deprotonated First, To Give The "Conjugate Base" Of The Substrate E1cB, Step 1: M H H3C H SH H3C LG alpha carbon (attached to LG) ß = beta carbon (attached to H) B-H M H H₂C B H3C LG conjugate base LG leaving group (e.g. Br) Bonds Bonds Formed Broken CB-H B-H

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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