10. According to the 1H NMR spectrum of the product, which of the following is a major product of the reaction sequence shown in the box? COCH3 CH3COCH,CH3 HCI, H20 HNO3 ? H2SO4 CH3CH2O- cold CCH2C A) CH2CCH2CH3 B) to he O,N elo NO2 Oonod-odiob CH,COCH,CH3 C) CH,COCH,CH3 ON 1H NMR of the major product: Expansion aromatic region: 1H, singlet 1H, doublet 1H, triplet 2H, singlet 3H, triplet twollol s doldW. 1H, doublet 2H, quartet PPM 0-

10. According to the 1H NMR spectrum of the product, which of the following is a major product of the reaction sequence shown in the box? COCH3 CH3COCH,CH3 HCI, H20 HNO3 ? H2SO4 CH3CH2O- cold CCH2C A) CH2CCH2CH3 B) to he O,N elo NO2 Oonod-odiob CH,COCH,CH3 C) CH,COCH,CH3 ON 1H NMR of the major product: Expansion aromatic region: 1H, singlet 1H, doublet 1H, triplet 2H, singlet 3H, triplet twollol s doldW. 1H, doublet 2H, quartet PPM 0-

EBK A SMALL SCALE APPROACH TO ORGANIC L

4th Edition

ISBN:9781305446021

Author:Lampman

Publisher:Lampman

Chapter61: Friedel–crafts Acylation

Section: Chapter Questions

Problem 8Q

See similar textbooks

Similar questions

Be sure to AUSTET All parts. Select the meckanistic steps thRE Tould produce "major prodoct Y" via a 12-bydride shift daring a dehydration of "alcobol X". major product Part 1: Seep 1: Part 2: Sep 2: OH 121 HSO, * HSO *HS0, Part 3: Step 3: Part 4 out of 4 Step 4: 14 HSO, HSO, 141 141 HSO FOSH Naxt part
Provide the complete mechanism using CAF for the reaction shown below. Tell how many signals are visualized in the 1H spectrum for the starting material and the product. H₂O, H₂SO4 gr=gr NH₂ heat OH + NH4+ HSO4
Jj.198.
Electrophilic Aromatic Substitution: Friedel-Crafts Alkylation please include experimental literature
looking at this reaction (first image), The second image shows the 13C NMR spectrum of the 2-acetnaphthone which is the starting material and an 13C NMR spectrum obtained for the reaction product: Based a comparison of the two 13C NMR spectra, is product A or product B the major product of the reaction? - Explain your reasoning.
Hexamethylbenzene undergoes free-radical chlorination to give one monochlorinated product (C12H17Cl) and four dichlorinated products (C12H16Cl2). These products are easily separated by GC-MS, but the dichlorinated products are difficultto distinguish by their mass spectra. Draw the monochlorinated product and the four dichlorinated products, and explainhow 13C NMR would easily distinguish among these compounds.1
Hexamethylbenzene undergoes free-radical chlorination to give one monochlorinated product (C12H17Cl) and four dichlorinated products (C12H16Cl2). These products are easily separated by GC-MS, but the dichlorinated products are difficultto distinguish by their mass spectra. Draw the monochlorinated product and the four dichlorinated products, and explainhow 13C NMR would easily distinguish among these compounds
3. Identify compounds A-I in the following synthesis scheme.
What is the H NMR for this molecule? Number of proton signals? Number of aromatic and alkene protons? Number of non-aromatic and non vinyl protons?
How many ¹H NMR signals are present in the product of the reaction shown below? O 9 07 8 o a 1) CH₂MgCl 2) H₂O
Please show mechanism
Bb.84.