In the diagram at right, switch S is initially closed, and the battery is driving a current counter-clockwise through the top loop. Suppose that the switch is opened at time t1, help open until time t2, and then closed again. Describe the current that will be induced in the bottom loop while all this occurs. O There will be a brief pulse of counter-clockwise current, both when S is opened and when it is closed. O There will be a brief pulse of counter-clockwise current when Sis opened, and then a brief pulse of clockwise current when S is closed. O There will be a steady clockwise current before S is opened, a steady counter-clockwise current while S remains open, and then a steady clockwise current again after S is closed. O There will be a brief pulse of clockwise current, both when S is opened and when it is closed. O There will be a brief pulse of clockwise current when S is opened, and then a brief pulse of counter-clockwise current when S is closed. O There will be no current before S is opened, a steady counter-clockwise current while S is open, and then no current again after S is closed.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
In the diagram at right, switch S is initially closed, and the battery is driving a current
counter-clockwise through the top loop. Suppose that the switch is opened at time t1,
help open until time t2, and then closed again. Describe the current that will be induced
in the bottom loop while all this occurs.
O There will be a brief pulse of counter-clockwise current, both when S is opened and when it is closed.
O There will be a brief pulse of counter-clockwise current when Sis opened, and then a brief pulse of clockwise current when S is closed.
O There will be a steady clockwise current before S is opened, a steady counter-clockwise current while S remains open, and then a steady clockwise current again after S is
closed.
O There will be a brief pulse of clockwise current, both when S is opened and when it is closed.
O There will be a brief pulse of clockwise current when S is opened, and then a brief pulse of counter-clockwise current when S is closed.
O There will be no current before S is opened, a steady counter-clockwise current while S is open, and then no current again after S is closed.
Transcribed Image Text:In the diagram at right, switch S is initially closed, and the battery is driving a current counter-clockwise through the top loop. Suppose that the switch is opened at time t1, help open until time t2, and then closed again. Describe the current that will be induced in the bottom loop while all this occurs. O There will be a brief pulse of counter-clockwise current, both when S is opened and when it is closed. O There will be a brief pulse of counter-clockwise current when Sis opened, and then a brief pulse of clockwise current when S is closed. O There will be a steady clockwise current before S is opened, a steady counter-clockwise current while S remains open, and then a steady clockwise current again after S is closed. O There will be a brief pulse of clockwise current, both when S is opened and when it is closed. O There will be a brief pulse of clockwise current when S is opened, and then a brief pulse of counter-clockwise current when S is closed. O There will be no current before S is opened, a steady counter-clockwise current while S is open, and then no current again after S is closed.
Expert Solution
Step 1

Initially, the switch was closed, so there was a uniform magnetic field because the current is constant. Thus, no changes in the magnetic field occur throughout the time until the switch is closed. After the switch is opened then there isn’t any current thus, nothing happens in this time span.

Step 2

At the time, when the switch is opened then the magnetic field decreases, and thus change in flux occurs. The changes in flux causes the induced current in the bottom loop. Using the Lenz law, the direction of the current in the bottom loop obtained as counter-clockwise.

steps

Step by step

Solved in 4 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON