In the cumulative distribution example below, P(X = 3/8) is equivalent to, 1 – P(X < 3/8). 3-52. + The thickness of wood paneling (in inches) that a customer orders is a random variable with the following cumu- lative distribution function: x<1/8 0.2 F(x)={ 1/81/4) (e) P(X<1/2) 18) » P(x=/2) • 0.20 f(14) - Plx= V4). 0.70 f/0/6) - P(x. %e) : 0. 10 %3D
In the cumulative distribution example below, P(X = 3/8) is equivalent to, 1 – P(X < 3/8). 3-52. + The thickness of wood paneling (in inches) that a customer orders is a random variable with the following cumu- lative distribution function: x<1/8 0.2 F(x)={ 1/81/4) (e) P(X<1/2) 18) » P(x=/2) • 0.20 f(14) - Plx= V4). 0.70 f/0/6) - P(x. %e) : 0. 10 %3D
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:In the cumulative distribution example below, P(X = 3/8) is equivalent to, 1 – P(X < 3/8).
3-52. + The thickness of wood paneling (in inches) that a
customer orders is a random variable with the following cumu-
lative distribution function:
x<1/8
|0.2
1/8< x<1/4
F(x)= {
|0.9
1/4 sx<3/8
1
3/8<x
Determine the following probabilities:
(a) P(X <1/18) (b) P(xs1/4) (e) P(X55/16)
(d) P(X >1/4) (e) P(X<1/2)
fe) - P( x=/e) • 0.20
f(14) - p(x= 14)- 0.70
f/0/1) = P(x: /2) : 0. 10
O True
False
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