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- The mean amount of time it takes a kidney stone to pass is 12 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X - N( 12 5 or or b. Find the probability that a randomly selected person with a kidney stone will take longer than 16 days to pass it. Hint: c. Find the minimum number for the upper quarter of the time to pass a kidney stone. days.Assume that a procedure yields a binomial distribution with n 1143 trials and the probability of success for one trial is p = 0.48. Find the mean for this binomial distribution. (Round answer to one decimal place.) Find the standard deviation for this distribution. (Round answer to two decimal places.) Use the range rule of thumb to find the minimum usual value u-20 and the maximum usual value p+2o. Enter answer as an interval using square-brackets only with whole numbers. usual values =Mark has a batting average of 0.17. Let X be the number of hits in his next 16 at bats. What is the distribution of X? X (,) Please show the following answers to 4 decimal places. What is the probability that he has exactly 7 hits? 0.0088 What is the probability that he has less than 7 hits?
- The mean amount of time it takes a kidney stone to pass is 13 days and the standard deviation is 6 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N( , ) b. Find the probability that a randomly selected person with a kidney stone will take longer than 9 days to pass it. ___c. Find the minimum number for the upper quarter of the time to pass a kidney stone. ___ days.The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.8 mm. Round values to 4 decimal places when possible. b. The standard deviation is c. The probability that the round a. The mean of this distribution is off error for a jumper's distance is exactly 0.3 is P(x-03)-d. The probability that the round off error for the distance that a long jumper has jumped is between 0 and 5 8 mm is PC1.7 x 5.2)- that the jump's round off error is greater than 1.76 is P(x > 1.76) Find the 81st percentile. e. The probability f P(x > 1.4 x > 0.6) h. Find the mnmum for the upper quartile.The time that it takes for the next train to come follows a Uniform distribution with f(x) =1/50 where x goes between 2 and 52 minutes. Round answers to 4 decimal places when possible. A. This is a Uniform or Normal distribution? B. Is it a Discrete or Continuous distribution? C. What is the mean of this distribution?
- The age of children in kindergarten on the first day of school is uniformly distributed between 4.91 and 5.97 years old. A first time kindergarten child is selected at random. Round answers to 4 decimal places if possible. a. The mean of this distribution is b. The standard deviation is c. The probability that the the child will be older than 5 years old?Find the 68th percentileFor binomial distribution, the mean is 4 and n = 8. what is π for this distribution?
- The time that it takes for the next train to come follows a Uniform distribution with f(x) =1/20 where x goes between 1 and 21 minutes. Round answers to 4 decimal places when possible. a. This is a Select an answer distribution. b. It is a Select an answer v distribution. c. The mean of this distribution is d. The standard deviation is e. Find the probability that the time will be at most 13 minutes. f. Find the probability that the time will be between 6 and 16 minutes. g. Find the 30th percentile. h. Find the probability that the time is more than 17 minutes given (or knowing that) it is at least 3 minutes.Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3.8 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. The mean of this distribution is The standard deviation is The probability that fawn will weigh exactly 2.4 kg is P(x = 2.4) = The probability that a newborn fawn will be weigh between 2.9 and 3.7 is P(2.9 < x < 3.7) = The probability that a newborn fawn will be weigh more than 2.72 is P(x > 2.72) = P(x > 2.8 | x < 3.5) = Find the 25th percentile.Today, the waves are crashing onto the beach every 4.7 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 4.7 seconds. Round to 4 decimal places where possible. d. The probability that the wave will crash onto the beach between 1.7 and 3.5 seconds after the person arrives is P(1.7 < x < 3.5) = ? e. The probability that it will take longer than 2.44 seconds for the wave to crash onto the beach after the person arrives is P(x ≥≥ 2.44) = ? f. Find the minimum for the upper quartile. ? seconds
