In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasVowel(). Your task is to define the hasVowel() function which has the following details Return type - int Name - hasVowel Parameter: char* - to hold the character array Return value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking.
In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasVowel(). Your task is to define the hasVowel() function which has the following details Return type - int Name - hasVowel Parameter: char* - to hold the character array Return value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
CODE USING C++
3. The proposal!
by CodeChum Admin
Thanks to your help again, I found the perfect ring for her. I'm going to propose tomorrow but I'm nervous. I think when I'm going to ask her the famous question, "Will you marry me?", she's going to respond with:
"Only if you can determine if there is a vowel in a certain word"
Shucks! It's always better to be prepared. Who knows that might indeed happen. I'm going to need your help to create function that'll do this so tomorrow, I will just call this function.
Instructions:
- In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasVowel().
-
Your task is to define the hasVowel() function which has the following details
- Return type - int
- Name - hasVowel
-
Parameter:
- char* - to hold the character array
- Return value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking.
Input
1. The word
Output
Enter·the·word:·CodeChum
There·is·a·vowel·in·the·word·"CodeChum"
![main.cpp
+
C++
"Only if you can determine if there is a vowel in a certain word"
1 #include <iostream>
Shucks! It's always better to be prepared. Who knows that might indeed
2 using namespace std;
happen. I'm going to need your help to create function that'll do this so
3
4 int main(void) {
char word[100];
tomorrow, I will just call this function.
6
7
cout <« "Enter the word: ";
cin >> word;
Instructions:
8
9
1. In the code editor, you are provided a main() function that asks
10
int result = hasVowel(word);
the user for a word. This word is then passed to a function called,
hasVowel().
2. Your task is to define the hasVowel() function which has the
following details
11
if(result == 1) {
cout <« "There is a vowel in the word \"" << word << "\"":
12
13
14
} else if(result == 0) {
1. Return type - int
15
cout <« "There is no vowel in the word \"" << word << "\"":
16
}
2. Name - hasvowel
17
3. Parameter:
18
return 0;
1. char* - to hold the character array
19 }
4. Return value - 1 if there is at least 1 vowel and 0 if there is
none. Be sure to consider both the capital and small letter
vowels when checking.
Input
1. The word
Output
Enter the word: Codechum
There is a vowel in the word "CodeChum"](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6811427c-5cb2-4236-853f-6e2e2426c5ba%2F4596b4f5-dacf-4f7b-b0b0-47eec61e8887%2Fds1vm2_processed.png&w=3840&q=75)
Transcribed Image Text:main.cpp
+
C++
"Only if you can determine if there is a vowel in a certain word"
1 #include <iostream>
Shucks! It's always better to be prepared. Who knows that might indeed
2 using namespace std;
happen. I'm going to need your help to create function that'll do this so
3
4 int main(void) {
char word[100];
tomorrow, I will just call this function.
6
7
cout <« "Enter the word: ";
cin >> word;
Instructions:
8
9
1. In the code editor, you are provided a main() function that asks
10
int result = hasVowel(word);
the user for a word. This word is then passed to a function called,
hasVowel().
2. Your task is to define the hasVowel() function which has the
following details
11
if(result == 1) {
cout <« "There is a vowel in the word \"" << word << "\"":
12
13
14
} else if(result == 0) {
1. Return type - int
15
cout <« "There is no vowel in the word \"" << word << "\"":
16
}
2. Name - hasvowel
17
3. Parameter:
18
return 0;
1. char* - to hold the character array
19 }
4. Return value - 1 if there is at least 1 vowel and 0 if there is
none. Be sure to consider both the capital and small letter
vowels when checking.
Input
1. The word
Output
Enter the word: Codechum
There is a vowel in the word "CodeChum"
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