CODE USING C++ 4. Secret Division by CodeChum Admin You're just in time! I'm now on a secret mission. I'm currently inside the enemy's labs and I need to break through their security. It seems that it requires some division but I think if I use the division sign, their alarms would go off. I need to find a way to perform division without using the division sign... Aha! Right! Repetitive Subtraction is the key! Can you help me with this, Programmer? Instructions: In the code editor, there is already a main() function that asks the user to input 2 integers: one for the dividend (the number found at the left side of the division) and one for the divisor (the number found at the right side of the division). In addition, there's also a call to the divide() function already. Your task is to implement the divide() function's definition by using recursion. DO NOT USE THE DIVISION OPERATOR. Also, do not edit anything in the main() Input 1. The dividend 2. The divisor Output Enter the dividend: 10 Enter the divisor:·5 10 / 5 = 2
CODE USING C++ 4. Secret Division by CodeChum Admin You're just in time! I'm now on a secret mission. I'm currently inside the enemy's labs and I need to break through their security. It seems that it requires some division but I think if I use the division sign, their alarms would go off. I need to find a way to perform division without using the division sign... Aha! Right! Repetitive Subtraction is the key! Can you help me with this, Programmer? Instructions: In the code editor, there is already a main() function that asks the user to input 2 integers: one for the dividend (the number found at the left side of the division) and one for the divisor (the number found at the right side of the division). In addition, there's also a call to the divide() function already. Your task is to implement the divide() function's definition by using recursion. DO NOT USE THE DIVISION OPERATOR. Also, do not edit anything in the main() Input 1. The dividend 2. The divisor Output Enter the dividend: 10 Enter the divisor:·5 10 / 5 = 2
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
CODE USING C++
4. Secret Division
by CodeChum Admin
You're just in time! I'm now on a secret mission.
I'm currently inside the enemy's labs and I need to break through their security. It seems that it requires some division but I think if I use the division sign, their alarms would go off. I need to find a way to perform division without using the division sign...
Aha! Right! Repetitive Subtraction is the key! Can you help me with this, Programmer?
Instructions:
- In the code editor, there is already a main() function that asks the user to input 2 integers: one for the dividend (the number found at the left side of the division) and one for the divisor (the number found at the right side of the division). In addition, there's also a call to the divide() function already.
- Your task is to implement the divide() function's definition by using recursion. DO NOT USE THE DIVISION OPERATOR.
- Also, do not edit anything in the main()
Input
1. The dividend
2. The divisor
Output
Enter the dividend: 10
Enter the divisor:·5
10 / 5 = 2
![main.cpp
+
C++
Tests
1 #include <iostream>
2 using namespace std;
CE Run Tests
3
4 int divide(int, int);
5
Constraints
6 int main(void) {
7
int dividend, divisor;
8
O Constraint 1
cout <« "Enter the dividend: ";
cin >> dividend;
Should not change main.
10
11
12
cout <« "Enter the divisor: ";
13
cin >> divisor;
O Constraint 2
14
The 'divide' function should apply recursion.
15
cout <« dividend <« " / " « divisor « " = " << divide(divide
16
17
return 0;
Test Cases
18 }
19
O Test Case 1
20 int divide(int dividend, int divisor) {
// TODO: Implement this function
21
...
22 }
Your Output
No Output
Expected Output
Enter the dividend: 10
Enter the divisor: 5
10 / 5 = 2
O Test Case 2
Execute Code [F10]
Submit Code
: Launch me](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7ab46b5-74ee-4a39-9c97-b4c8aeb6b8c3%2Fad2d8032-f3cd-4917-a1b2-7455c64ba5c8%2Fic8gylg_processed.png&w=3840&q=75)
Transcribed Image Text:main.cpp
+
C++
Tests
1 #include <iostream>
2 using namespace std;
CE Run Tests
3
4 int divide(int, int);
5
Constraints
6 int main(void) {
7
int dividend, divisor;
8
O Constraint 1
cout <« "Enter the dividend: ";
cin >> dividend;
Should not change main.
10
11
12
cout <« "Enter the divisor: ";
13
cin >> divisor;
O Constraint 2
14
The 'divide' function should apply recursion.
15
cout <« dividend <« " / " « divisor « " = " << divide(divide
16
17
return 0;
Test Cases
18 }
19
O Test Case 1
20 int divide(int dividend, int divisor) {
// TODO: Implement this function
21
...
22 }
Your Output
No Output
Expected Output
Enter the dividend: 10
Enter the divisor: 5
10 / 5 = 2
O Test Case 2
Execute Code [F10]
Submit Code
: Launch me
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