In the circuit shown, the BJT (Bipolar Junction Transistor) has the following parameters: - Current gain, \( \beta = 100 \)- Base-emitter voltage, \( V_{BE} = 0.7 \, \text{V} \)- Saturation voltage, \( V_{CEsat} = 0.2 \, \text{V} \)As long as the BJT remains in the active region, the circuit provides constant \( I_0 \), which is only dependent on \( V_{BB} \). For \( V_{BB} = 2 \, \text{V} \) and \( R_B = 13 \, \text{K Ohms} \):A) Find \( I_0 \) for \( R_E = 0 \).B) Find \( I_0 \) for \( R_E = 100 \, \text{Ohms} \).C) For \( R_E = 100 \, \text{Ohms} \), find the lowest \( V_{CC} \) before the BJT saturates.**Diagram Explanation:**The diagram shows a simple BJT circuit. Key components include:- A resistor \( R_B = 13 \, \text{K Ohms} \) connected to the base of the transistor.- An input voltage \( V_{BB} = 2 \, \text{V} \) applied alongside \( R_B \).- The collector is connected to \( V_{CC} \), the supply voltage.- The emitter is connected to \( R_E \), which varies.- \( I_0 \) is the current flowing through the collector from \( V_{CC} \). The objective is to determine the effects of \( R_E \) and \( V_{CC} \) on the circuit behavior, particularly \( I_0 \) and saturation conditions.

Given circuit is, Following data is also given, β = 100VBE = 0.7 VVCEsat = 0.2 V The required parameters can be calculated by using the DC analysis of the circuit.(A) Io for RE=0, Apply mesh analysis in the base emitter loop and simplify to calculate the base current. IB = VBB-VBERB+(1+β)REIB = 2-0.713KΩ+(1+100)0 = 1.313000IB = 0.1 mA Now, calculate the collector current using below formula. Io=Ic=βIB = 100×0.1 mAIo = 10 mA (B) Io for RE=100 Ω, Apply mesh analysis in the base emitter loop and simplify to calculate the base current. IB = VBB-VBERB+(1+β)REIB = 2-0.713KΩ+(1+100)100 = 1.323.1 KΩIB = 56.28 μA Now, calculate the collector current using below formula. Io=Ic=βIB = 100×56.28 μAIo = 5.63 mA(C) Lowest Vcc for RE = 100 Ω, Apply mesh analysis in the collector emitter loop and simplify. Use the required value from subpart (B). VCESat = VCC-IERE0.2 = VCC-((100+1)×56.28×10-6 )(100)0.2 = VCC-0.5684VCC = 0.2 + 0.5684VCC = 0.7684 V So, lowest Vcc before the BJT saturates is 0.7684 V.