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In the circuit of Fig. 8_4, what is Ve(t) for 1>0? 100 8u(t) V 100 V.(0)=2V Fig. 8 4 V.(t)-2 (2-e02) u(t) (V) V.(t)-2 (2+ e02) u(t) (V) V(t)-2 (5-e-0.6) u(t) (V) V.(t)-2 (5+06) u(t) (V) IF: + V.(1)

In the circuit of Fig. 8_4, what is Ve(t) for 1>0? 100 8u(t) V 100 V.(0)=2V Fig. 8 4 V.(t)-2 (2-e02) u(t) (V) V.(t)-2 (2+ e02) u(t) (V) V(t)-2 (5-e-0.6) u(t) (V) V.(t)-2 (5+06) u(t) (V) IF: + V.(1)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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### Transcription of Educational Content **Circuit Analysis** In the circuit of Fig. 8_4, what is \( V_c(t) \) for \( t > 0 \)? **Circuit Diagram** - The circuit consists of a voltage source, \( 8u(t) \) V, in series with a 10Ω resistor. - This series combination is connected parallel to a 1F capacitor labeled with voltage \( V_c(t) \). - There is also a 10Ω resistor in series with the capacitor. The initial voltage across the capacitor is \( V_c(0) = 2V \). **Figure: Fig. 8_4** **Multiple Choice Options:** - \( V_c(t) = 2 (2 - e^{-0.2t}) u(t) \) (V) - \( V_c(t) = 2 (2 + e^{-0.2t}) u(t) \) (V) - \( V_c(t) = 2 (5 - e^{-0.6t}) u(t) \) (V) - \( V_c(t) = 2 (5 + e^{-0.6t}) u(t) \) (V)
Transcribed Image Text:### Transcription of Educational Content **Circuit Analysis** In the circuit of Fig. 8_4, what is \( V_c(t) \) for \( t > 0 \)? **Circuit Diagram** - The circuit consists of a voltage source, \( 8u(t) \) V, in series with a 10Ω resistor. - This series combination is connected parallel to a 1F capacitor labeled with voltage \( V_c(t) \). - There is also a 10Ω resistor in series with the capacitor. The initial voltage across the capacitor is \( V_c(0) = 2V \). **Figure: Fig. 8_4** **Multiple Choice Options:** - \( V_c(t) = 2 (2 - e^{-0.2t}) u(t) \) (V) - \( V_c(t) = 2 (2 + e^{-0.2t}) u(t) \) (V) - \( V_c(t) = 2 (5 - e^{-0.6t}) u(t) \) (V) - \( V_c(t) = 2 (5 + e^{-0.6t}) u(t) \) (V)
Expert Solution
Step 1: Determination of given parameters,

The circuit diagram,

Electrical Engineering homework question answer, step 1, image 1

The initial voltage across the capacitor, V subscript c open parentheses 0 to the power of minus close parentheses equals 2 space V

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