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Linear Second-Order Equations Find the current in the RLC circuit, assuming that E(t) = 0 for t > 0 R = 4 ohms; L = .05 henrys; C = .008 farads; Q0 = -1 coulombs; I0 = 2 amperes I need help to finding the current

Linear Second-Order Equations Find the current in the RLC circuit, assuming that E(t) = 0 for t > 0 R = 4 ohms; L = .05 henrys; C = .008 farads; Q0 = -1 coulombs; I0 = 2 amperes I need help to finding the current

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Linear Second-Order Equations

Find the current in the RLC circuit, assuming that E(t) = 0 for t > 0

R = 4 ohms; L = .05 henrys; C = .008 farads; Q0 = -1 coulombs; I0 = 2 amperes

I need help to finding the current

We have Pulting all Let I the differential equation, = the values d²f 0.05 dt² + +80. 80 det inte we 4 dt2 be the trial Hence general sollution, have det s + dt Aext Hence auxiliary equation, -> x = +2500 1 = 0 I(t) = sollution of I 0.008 x = e L -802 -40t d²I dt² c 9² +80x + 2500 80 di R = + = = 0 곧 dt 2 + R =0 4x2500 - 40 ± 30 { c₁cos (30t) + C₂ sin (30+)} [c1, c₂ are constants ]
Transcribed Image Text:We have Pulting all Let I the differential equation, = the values d²f 0.05 dt² + +80. 80 det inte we 4 dt2 be the trial Hence general sollution, have det s + dt Aext Hence auxiliary equation, -> x = +2500 1 = 0 I(t) = sollution of I 0.008 x = e L -802 -40t d²I dt² c 9² +80x + 2500 80 di R = + = = 0 곧 dt 2 + R =0 4x2500 - 40 ± 30 { c₁cos (30t) + C₂ sin (30+)} [c1, c₂ are constants ]
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