In the 1992 presidential election, Alaska's 40 election districts averaged 1881 votes per district for President Clinton. The standard deviation was 575. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X~ N( b. Is 1881 a population mean or a sample mean? Select an answer c. Find the probability that a randomly selected district had fewer than 1739 votes for President Clinton.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.5: Comparing Sets Of Data
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In the 1992 presidential election, Alaska's 40 election districts averaged 1881 votes per district for President Clinton. The standard deviation was 575.
(There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for
President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.
a. What is the distribution of X? X~ N(
b. Is 1881 a population mean or a sample mean? Select an answer
c. Find the probability that a randomly selected district had fewer than 1739 votes for President Clinton.
d. Find the probability that a randomly selected district had between 1873 and 2094 votes for President Clinton.
e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
Transcribed Image Text:In the 1992 presidential election, Alaska's 40 election districts averaged 1881 votes per district for President Clinton. The standard deviation was 575. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X~ N( b. Is 1881 a population mean or a sample mean? Select an answer c. Find the probability that a randomly selected district had fewer than 1739 votes for President Clinton. d. Find the probability that a randomly selected district had between 1873 and 2094 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
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