A pharmaceutical company makes tranquilizers. We wish to find the 89% confidence interval. It is assumed that the distribution for the length of time they last is approximately normal. The standard deviation for all lengths of time for the tranquilizer is 0.21 hours. Researchers in a hospital used the drug on a random sample of 33 patients. The effective period of the tranquilizer for each patient (in hours) is shown in the table below. Round all answers to the nearest hundredth. 2.2 2.79 2.8 2.64 2.53 2.57 2.31 2.25 2.76 2.61 2.11 2.28 2.22 2.81 2.95 2.1 2.33 2.83 2.71 2.96 2.49 2.72 2.23 2.15 2.81 2.45 2.38 2.63 2.54 2.37 2.76 2.27 2.69 (a) = 41.625 (b) s = (c) σ= 0.21 * Enter DNE if this is unknown. Enter DNE if this is unknown. (d) n = = 33 (e) Critical Value z (f) Find the 89% confidence interval and complete the sentence below. Conclusion: We estimate with 89 and ✓= 5.5 hours. % confidence that the mean time in hours for the tranquilizer is between
A pharmaceutical company makes tranquilizers. We wish to find the 89% confidence interval. It is assumed that the distribution for the length of time they last is approximately normal. The standard deviation for all lengths of time for the tranquilizer is 0.21 hours. Researchers in a hospital used the drug on a random sample of 33 patients. The effective period of the tranquilizer for each patient (in hours) is shown in the table below. Round all answers to the nearest hundredth. 2.2 2.79 2.8 2.64 2.53 2.57 2.31 2.25 2.76 2.61 2.11 2.28 2.22 2.81 2.95 2.1 2.33 2.83 2.71 2.96 2.49 2.72 2.23 2.15 2.81 2.45 2.38 2.63 2.54 2.37 2.76 2.27 2.69 (a) = 41.625 (b) s = (c) σ= 0.21 * Enter DNE if this is unknown. Enter DNE if this is unknown. (d) n = = 33 (e) Critical Value z (f) Find the 89% confidence interval and complete the sentence below. Conclusion: We estimate with 89 and ✓= 5.5 hours. % confidence that the mean time in hours for the tranquilizer is between
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A pharmaceutical company makes tranquilizers. We wish to find the 89% confidence interval. It is assumed that the
distribution for the length of time they last is approximately normal. The standard deviation for all lengths of time for
the tranquilizer is 0.21 hours. Researchers in a hospital used the drug on a random sample of 33 patients. The effective
period of the tranquilizer for each patient (in hours) is shown in the table below. Round all answers to the nearest
hundredth.
S
O
2.2 2.79 2.8 2.64
2.53
2.57 2.31
2.25 2.76 2.61
2.95
2.11 2.28 2.22 2.81
2.1 2.33 2.83 2.71 2.96
2.49 2.72 2.23 2.15 2.81
2.45 2.38 2.63 2.54 2.37
2.76 2.27 2.69
(a) = 41.625
(b) s =
(c) o =
(d) n = 33
0.21
*
8
(e) Critical Value z
(f) Find the 89% confidence interval and complete the sentence below.
*
Conclusion: We estimate with 89
and
O
Enter DNE if this is unknown.
✔
9
Enter DNE if this is unknown.
acer
✓
0
hours.
5.5
% confidence that the mean time in hours for the tranquilizer is between
D
ن
backspace
D
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Transcribed Image Text:=/391785?module_item_id=965498
A pharmaceutical company makes tranquilizers. We wish to find the 89% confidence interval. It is assumed that the
distribution for the length of time they last is approximately normal. The standard deviation for all lengths of time for
the tranquilizer is 0.21 hours. Researchers in a hospital used the drug on a random sample of 33 patients. The effective
period of the tranquilizer for each patient (in hours) is shown in the table below. Round all answers to the nearest
hundredth.
S
O
2.2 2.79 2.8 2.64
2.53
2.57 2.31
2.25 2.76 2.61
2.95
2.11 2.28 2.22 2.81
2.1 2.33 2.83 2.71 2.96
2.49 2.72 2.23 2.15 2.81
2.45 2.38 2.63 2.54 2.37
2.76 2.27 2.69
(a) = 41.625
(b) s =
(c) o =
(d) n = 33
0.21
*
8
(e) Critical Value z
(f) Find the 89% confidence interval and complete the sentence below.
*
Conclusion: We estimate with 89
and
O
Enter DNE if this is unknown.
✔
9
Enter DNE if this is unknown.
acer
✓
0
hours.
5.5
% confidence that the mean time in hours for the tranquilizer is between
D
ن
backspace
D
Oct 19 1:23 1
page up
delete
page dn
home
1
D
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