In testing for differences between the means of two independent populations the null hypothesis is: O A. H iH,-H2=2 O B. Ho:H1 -H2<0 OC. Ho:H1-H2>0 O D. H H,-H2=0
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- Test the claim that the mean GPA of night students is larger than 3.2 at the 0.01 significance level. The null and alternative hypotheses would be: Но: д — 3.2 Но: р — 3.2 Но:р — 3.2 Но:р — 0.8 Но:р — 0.8 Но:р — 0.8 0.8 Ho:p %3D Hi:д 3.2 Ні:д 3.2 Hi:р > 0.8 H:р < 0.8 Ні:р 0.8 The test is: right-tailed two-tailed left-tailed Based on a sample of 31 people, the sample mean GPA was 3.24 with a standard deviation of 0.14 The p-value is: | (to 3 decimals) The significance level is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesisAn experiment was performed with three treatments (A, B, and C). Which of the following is a correct model with a categorical explanatory variable with three categories? yˆ = a +bx where x = 0 if in treatment A, x = 1 if in treatment B, and x= 2 if in treatment C yˆ = a +bxA + cxB + dxC where xA = 1 if in treatment A, and = 0 if not in treatment A xB = 1 if in treatment B, and = 0 if not in treatment B xC = 1 if in treatment C, and = 0 if not in treatment C yˆ = a + bxA + cxB where xA = 1 if in treatment A, and = 0 if not in treatment A xB = 1 if in treatment B, and = 0 if not in treatment BHypothesis Test for a Population Proportion Test the claim that the proportion of men who own cats is significantly different than 20% at the 0.2 significance level. The test is based on a sample of 30 people, in which 19% of the sample owned cats. The null and alternative hypothesis would be: Но: и — 0.2 Но:р — 0.2 Но: д — 0.2 Но: и 0.2 H1: µ + 0.2 H1:p 0.2 Ho:p = 0.2 Ho:p = 0.2 Нi:р + 0.2 Н]:р> 0.2 The test is: two-tailed left-tailed right-tailed The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
- A researcher hypothesized that score differed between the first and the last rounds of major U.S. golf tournaments. Here are the paired data for randomly selected golfers from the 2021 U.S. Open. At the 0.05 level of significance , is there a difference? The score of major golf tournaments Golfer 1 3 4 5 6 Round 1 185 178 175 183 193 173 Round 2 171 180 173 175 188 178 The hypothesis test is as following: Ho: Hd = 0 H1: µd #0 Test statistic t Hint: Find d-bar and Sd, then find the test statistic.The following table contains the number of successes and failures for three categories of a variable. Test whether the proportions are equal for each category at the α=0.1 level of significance. Category 1 Category 2 Category 3 Failures 32 51 57 Successes 39 54 73 State the hypotheses. Choose the correct answer below. A. H0: The categories of the variable and success and failure are independent. H1: The categories of the variable and success and failure are dependent. B. H0: The categories of the variable and success and failure are dependent. H1: The categories of the variable and success and failure are independent. C. H0: p1=p2=p3 H1: At least one of the proportions is different from the others. D. H0: μ1=E1 and μ2=E2 and μ3=E3 H1: At least one mean is different from what is expected. What is the P-value? nothing (Round to three decimal places as needed.) What conclusion can be…A researcher hypothesized that score differed between the first and the last rounds of major U.S. golf tournaments. Here are the paired data for randomly selected golfers from the 2021 U.S. Open. At the 0.05 level of significance , is there a difference? The score of major golf tournaments Golfer 1 4 Round 1 185 178 175 183 193 173 Round 2 171 180 173 175 188 178 The hypothesis test is as following: Ho: µa = 0 H1: µd #0 Test statistict Hint: Find d-bar and Sd, then find the test statistic.
- Test the claim that the proportion of men who own cats is significantly different than 70% at the 0.1 significance level. The null and alternative hypothesis would be: Но: р 3 0.7 Но:д — 0.7 Но:д %3D 0.7 Но:р — 0.7 Но:р — 0.7 Но: д — 0.7 H:р +0.7 H:n # 0.7 Hi:р > 0.7 H:p > 0.7 H:р < 0.7 H:р < 0.7 The test is: two-tailed left-tailed right-tailed Based on a sample of 55 people, 75% owned cats The test statistic i: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesisTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.1 significance level.The null and alternative hypothesis would be: A.) H0:μM=μF H1:μM≠μF B.)H0:μM=μF H1:μM<μF C.)H0:pM=pF H1:pM<pF D.)H0:pM=pF H1:pM≠pF E.)H0:μM=μF H1:μM>μF F.)H0:pM=pF H1:pM>pF The test is: A.) right-tailed B.) left-tailed C.) two-tailed Based on a sample of 40 men, 40% owned catsBased on a sample of 20 women, 55% owned cats The test statistic is:___________ (to 2 decimals)The p-value is: _____________ (to 2 decimals)Based on this we: A.) Reject the null hypothesis B.) Fail to reject the null hypothesisTest the claim that the mean GPA of night students is larger than 2 at the 0.10 significance level. The null and alternative hypothesis would be: Họ :p = 0.5 Họ:µ = 2 Ho:u 0.5 Ho:p 2 H1 :p + 0.5 H1:µ # 2 H1:µ > 2 H1:p 0.5 H1:µ < 2 The test is: left-tailed right-tailed two-tailed Based on a sample of 25 people, the sample mean GPA was 2.02 with a standard deviation of 0.05 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
- Test the claim that the proportion of men who own cats is larger than 20% at the .05 significance level. The null and alternative hypothesis would be: 0.2 Но: р — 0.2 Но: д 0.2 Но:р Но: и Н: + 0.2 Н]:р 0.2 Hi:д > 0.2 Hi:р+0.2 0.2 Но:р — 0.2 Но: д 0.2 The test is: left-tailed two-tailed right-tailed Based on a sample of 25 people, 25% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis Reject the null hypothesisTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.01 significance level. The null and alternative hypothesis would be: A.)H0:pM=pF H1:pM>pF B.)H0:pM=pF H1:pM≠pF C.)H0:μM=μF H1:μM≠μF D.)H0:pM=pF H1:pM<pF E.)H0:μM=μF H1:μM>μF F.)H0:μM=μFH0:μM=μF H1:μM<μFH1:μM<μF The test is: A.) left-tailed B.) right-tailed C.) two-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 60 women, 50% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: A.) Fail to reject the null hypothesis B.) Reject the null hypothesis20. Which of the following is a null hypothesis? a. Pregnant women who drink cranberry juice will have lower urine bacterial counts than those who do not drink cranberry juice. b. The urine bacterial count of pregnant women who drink cranberry juice will be lower or equal to that of pregnant women who do not drink the juice. c. There will be a difference between ingestion of cranberry juice and among pregnant women who do and do not have high urine bacterial counts.