In survey 500 students are selected randomly 230 say that they believe in their perents decisions are good construct 90% confidence interval for the population proportion of students who believe that their perents decision are good is.
Q: A survey was conducted that asked 1017 people how many books they have written in the past year…
A: Given that, x¯=14.1,s=16.6,n=1017 The degree of freedom is, df=n-1 =1017-1 =1016
Q: Tik Tok has yet to produce a decent advertisement strategy. Recently, 350 Tik Tok users were asked…
A: 1. There are 350 Tik Tok users were asked about ads. in which 50 of them responded that they did not…
Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…
A: Given data, n=2255 x=1787 sample proportion p=x/n =1787/2255 = 0.792 z-value at 90% confidence…
Q: A collage professor would like to estimate the proportion of students who pull an *all-nighter,"…
A: Given: n = 100 99% Confidence interval = (0.48 to 0.62) Formula Used: Confidence interval = p^ ±…
Q: A random sample of 861 birds in a state, including 422 boys construct a 95% confidence interval…
A: Sample size, Number of boys, Confidence level,
Q: TLD Insurance company decided to check 588 random accident reports and they find that out of 588, 84…
A:
Q: All patients admitted to a particular hospital can be released on the same day or kept overnight for…
A:
Q: From an SRS of 750 16-35 year olds in the U.S.434 indicated that they felt Netflix was…
A: given;n=750x=434p=434750for confidence level 95%,significance level (α)α=1-95%α=1-0.95α=0.05now, z…
Q: Suppose bootstrap_medians is a large array of bootstrapped medians and we want to use it to…
A: For 95% confidence level, the level of significance α will be 5% =(100-95)%. The level of…
Q: ur UI me proportion confhdence interval problems. be 6Š JUmpe S12e A survey of 500 non-fatal…
A:
Q: According to recent study, 173 of 489 CEOs in a certain country are extremely concerned about…
A: Here, Sample size=n=489Let x and p be the number and proportion, respectively of CEOs in the…
Q: In a sample of 16 fish from my pond it was found that 5 are under 165 grams in weight. Based on this…
A: Given information n = 16 fish No of fish under 165g (x) = 5
Q: A genetic experiment with peas resulted in one sample of offspring that are considered a 412 green…
A: According to the provided information, there are 412 green peas and 155 yellow peas making a total…
Q: After interviewing 30 third-year students, it is found that the sample mean of their happiness index…
A: Given,sample size(n)=30sample mean(x¯)=72standard deviation(s)=37degrees of…
Q: survey of 500 students are selected randomly 230 say that they believe in their perents decisions…
A: Given,n=500x=230p^=xnp^=230500=0.461-p^=1-0.46=0.54α=1-0.95=0.05α2=0.025Z0.025=1.96 (from Z-table)
Q: A survey of 1,898 adults with lawns conducted by a researcher found that 45% of the adults said that…
A: Obtain the 95% confidence interval of the true proportion who said that dandelions were the toughest…
Q: The last 20 apartments sold in the Neighborhood took an average of 180 days to sell with a st dev of…
A: σ = 30 , n = 20 , α= 0.02
Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…
A: It is given that the number of US adults is 2255, among them 1787 are uses the internet regularly.…
Q: simple random sample of size n = 350 individuals who are currently employed is asked if they work at…
A: Given n=350 x=31
Q: Suppose the mean height in inches of all 9th grade students at one high school is estimated. The…
A: Population standard deviation()=5sample size(n)=9The heights of 9 randomly selected students is…
Q: During a field trip by 200 level nursing students in fatika community screening exercise for…
A: Confidence interval comes under the concept of interval estimation. In interval estimation, we get a…
Q: study of 420,005 cell phone users found that 137 of them developed cancer of the brain or nervous…
A:
Q: The final grades of students in BC schools are randomly selected from various classes, namely 77,…
A:
Q: The annual incomes of a random sample of 10 individuals in a certain city are given below. Construct…
A:
Q: Twelve different video games showing drug usedrug use were observed. The duration times of drug…
A: Given Information significance level alpha = 0.10 confidence level = 1 - alpha = 1 - 0.1 = 0.9…
Q: A recent study states that high winds can affect the pollination rate of sunflowers. It reported…
A:
Q: In a survey, a random sample of teenagers were asked whether they have a sibling. The resulting…
A: Given confidence interval is (0.61 , 0.91)Upper limit=0.91Lower limit=0.61
Q: It is said that happy and healthy workers are efficient and productiveA company that manufactures…
A: We have to find ci.
Q: I'm a survey of 2589 adults 1500 say they have started paying bills online in the last year.…
A:
Q: a) Proportion of US adults who use the Internet regularly. Round your answers to three decimal…
A: The critical value corresponding to 90% confidence level from the standard normal table will be:…
Q: A medical study followed a sample of 14 heart patients who had received electronic pacemakers. The…
A:
Q: Conditions For each situation described below, identify the population and the sample, explain what…
A: Hi! Thanks for posting the question. Since there are more than three sub-part questions, we will…
Q: A researcher surveys 722 randomly selected Australians and asks them: "Do you believe that Climate…
A: Given data Number of people answered yes x = 468 Sample size (n) = 722
Q: Twelve different video games showing drug use were observed. The duration times of drug use were…
A: Here, the significance level is 0.10. The claim of the test is the population mean is greater than…
Q: In a survey of 3299 adults aged 57 through 85 years, it was found that 82.2% of them used at least…
A: It is given that sample size (n) is 3,299 and p hat value is 0.822.
Q: A survey of a 106 randomly selected students at 1 college showed that only 90 checked their campus…
A: Obtain the 90% confidence interval for the percentage of students at the college who do not check…
Q: survey 500 students are selected randomly 230 say that they believe in their perents decisions are…
A: In a survey 500 students are selected randomly 230 say that they believe in their parents decisions…
Q: The final grades of students in BC schools were chosen randoml from various classes, namely 77, 80,…
A: Given : n=6 , ƩX=446 , ƩX2=33948 The sample standard deviation is ,…
Q: A tire manufacturer tested the braking performance of one of its tire models on a test track. The…
A: There are two dependent samples which are dry pavement and wet pavement. We have to construct 95%…
Q: During a field trip by 200 level nursing students in fajita community screening exercise for…
A: We have to construction ci.
Q: In a survey of 150 randomly selected gun owners, it was found that 75 of them said they owned a gun…
A: Provided information is, in a survey of 150 randomly selected gun owners, it was found that 75 of…
In survey 500 students are selected randomly
230 say that they believe in their perents decisions are good
construct 90% confidence interval for the population proportion of students who believe that their perents decision are good is.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
- st Expressway Two separate surveys were carried out to investigate whether the users of East are in favor of raising the speed limit on highways. From 250 car drivers interviewed, 30 were not in favor of raising the speed limit. While among 200 motorcyclists interviewed, 20 were not in favor of raising the speed limit. Find a 93% confidence interval for the difference of population proportion between the car drivers and motorcyclists who are in favor of raising the speed limit. Interpret the interval.In a simple random sample of 9000 wooden artifacts near the Sluys, 5088 were made of cedar. Use this to construct a 99% confidence level confidence interval for the proportion of all wooden artifacts at that site which are made of cedar.The University of Chicago's General Social Survey (GSS) is the nation's most important social science sample survey. The GSS asked a random sample of adults their opinion about whether astrology is very scientific, sort of scientific, or not at all scientific. A two-way table of counts for people in the sample who had three levels of higher education degrees is given. Degree Held Bachelor Junior College Not at all scientific Very or sort of scientific 13 Identify a 95% confidence interval for the percentage of people with a junior college degree who think that astrology is not at all scientific. 0.4597 to 0.6729 0.1011 to 0.1745 0.0793 to 0.1377 0.4768 to 0.6558 47 36 Graduate 181 43 113
- A genetic experiment with peas resulted in one sample of a spring that consisted of 405 green peas and 152 yellow peas construct a 90% confidence interval to estimate the percentage of yellow peas based on the confidence info to the results of the experiment appear to contradict expectation that 25% of the offspring piece would be yellow?In a survey of 160 randomly selected gun owners, it was found that 80 of them said they owned a gun primarily for protection. Find the margin of error and 95% confidence interval for the percentage of all gun owners who would say that they own a gun primarily for protection. Report answers to 2 decimal places3) A local municipality tests 25 samples of water and finds that the mean concentration of chlorine in the water is 150 mg/l with a standard deviation of 18 mg/l. Construct a 90% confidence interval for your results and draw the interval. Hypothesis Testing Test#- Claim# Vn %3D pq
- Suppose we collected a sample and it passes the independence and success-failure conditions. The sample proportion we found was P^ (the actual value doesn’t matter, so we just use the symbol). Which would be bigger, a 90% confidence interval or a 95% confidence interval? WhyA nutrition and diet center selected 12 clients randomly and listed the weight they lost after the nutrition program in kg as follows. According to this, Number of clients Weight loss (kg) 3,2 2,1 4,6 1,8 1. 2 4 3,5 6. 2,2 1,9 7 8. 4,2 2,6 9. 10 1,7 11 4,3 12 5,2 1. Find and interpret the 95% confidence interval for the population mean. 2. If a confidence interval calculated for the population mean is found to be 2.62 - 3.59, find the confidence level of this range.If 13 of 200 male voters and 9 of 159 female voters favor a certain candidate running for governor_of Illinois, find a 99% confidence interval for the difference between the actual proportions of malė and female voters who favor the candidate.
- A random sample of 200 male shoppers in Pavilion shopping mall were interviewed to identify their reasons for coming to this particular mall. The factor of ‘I prefer Knox brand in the mall’ was the most important reason for 120 of those interviewed. Estimate the likely percentage of all male shoppers who frequent this shopping mall primarily because of the Knox brand in the mall, using 97.5% confidence limits.In a survey of 3299 adults aged 57 through 85 years, it was found that 82.2% of them used at least one prescription medication. a. How many of the3299 subjects used at least one prescription medication? ^ answer = 2712 b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. ^ answer = 81.10 % < p < 83.30% ***QUESTION*** c. What do the results tell us about the proportion of college students who use at least one prescription medication? choose. A. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). B. The results tell us nothing about the proportion of college students who use at least one prescription medication. C. The results tell us that, with 90% confidence, the probability that a college student uses at least one…During a field trip by 200 level nursing students in Koraye community screening exercise for genetype was among members of the community. Out of the 152 volunteers tested 21 had SS genotype. Calculate and interpret 95% confidence interval for the prevalence sickle cell disease in the community.