study of 420,005 cell phone users found that 137 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0415% for those not using cell phones. Complete parts (a) and (b). a) Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. _%
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- A sample of 1200 females and 1000 males found that 78.3% of females and 35.1% males supported increased funding of arts. Construct a 90% confidence interval around the difference in proportions.According to the website www.collegedrinkingprevention.gov, "About 25 percent of college students report academic consequences of their drinking including missing class, falling behind, doing poorly on exams or papers, and receiving lower grades overall." A statistics student is curious about drinking habits of students at his college. He wants to estimate the mean number of alcoholic drinks consumed each week by students at his college. He plans to use a 90% confidence interval. He surveys a random sample of 63 students. The sample mean is 3.7 alcoholic drinks per week. The sample standard deviation is 3.2 drinks. Construct the 90% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college. 1. The t value is - 2. The standard error has a value of -- 3. The margin of error has a value of 4. Construct the 90% confidence interval to estimate the average number of alcoholic drinks consumed each week by students at this college.The Aloha Taxi Cab Company of Honolulu, Hawaii, wants to estimate the mean life of tires on its cabs. A random sample of 15 tires from the cabs are found to have a life of 18,280 miles with sample standard deviation of 1,310 miles. Find a 90% confidence interval for the mean life of all such tires on Aloha Taxi Cabs.
- Kmart decided to inventory all of its furniture stock for a year end evaluation. At that time there were 768 items of furniture. A random sample of 40 items of furniture were selected for audit, with sample mean=$249.06 and SD=$92.58. Construct a 95% confidence interval estimate of the total value of furniture stock for year end.A study of 420,039 cell phone users found that 131 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0443% for those not using cell phones. Complete parts (a) and (b). ..... a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. • D%A study of 420,097 cell phone users found that 137 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0311% for those not using cell phones. Complete parts (a) and (b). .... a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %A sample of 6 credit ratings for car loan applicants has a mean of 602 and a variance of 4356. Use the data toconstruct a 90% confidence interval for the population standard deviation of credit scores for all applicantsfor car loans. What is the Best point estimate and Include the written statementA researcher studying reaction time of drivers states that, "A 95% confidence interval for the mean time it takes for a driver to apply the brakes after seeing the brake lights on a vehicle in front of him is 1.2 to 1.8 seconds." What are the point estimate and margin of error for this interval? Point estimate = 1.5 seconds; margin of error = 0.95 seconds. Point estimate = 1.2 seconds; margin of error = 0.3 seconds. Point estimate = 1.5 seconds; margin of error = 0.6 seconds. Point estimate = 1.5 seconds; margin of error = 0.3 seconds. a O b O dA study was done to determine whether there is a relationship between snoring and the risk of heart disease. Among 1,105 snorers in the study, 85 had heart disease, while only 21 of 1,379 nonsnorers had heart disease. In USE SALT (a) Determine a 95% confidence interval that estimates p, - p2 difference in proportions of snorers and nonsnorers who have heart disease. (Let p, be the proportion of snorers and p, be the proportion of nonsnorers. Round your answers to three decimal places.) |-0.079 X to -0.045SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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