In step 7, a hydroperoxide ion reacts with the glycosulose molecule to form a peroxy intermediate. vii. Draw the 2 arrows of this step. Step 7 is a nucleophilic attack. Why is the glycosulose attractive to nucleophiles like the hydroperoxide viii. ion?
Catalysis and Enzymatic Reactions
Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.
Lock And Key Model
The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
ONLY ANSWER vii and viii
![ene-diolate ion
STEP S
hydride produet of
STEP 5
glycosulose fom
BLUE, MB
hydroperoxide ion
STEP 6-b
STEP 6-a
Hydroperoxide ion
product of STEP
6-b
COLORLESS, MBH
Glycosulose product of
STEP5
STEP 7
[3] Draw the 3 arrows showing how STEP 6-a has a hydride attack the BLUE, MB* turning it a COLORLESS,
MBH form of methylene blue
V.
[2] step 6-b reverts MBH back to MB" as it reacts with o, gas. Determine between Step 6-a and Step 6-b
which was a reduction and which was an oxidation process for methylene blue.
vi.
Step 6-a was a
Step 6-b was a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab099c87-bf70-4c3d-87ef-08495addc0f9%2Fbea686d2-a830-46ed-bf9a-cd5d6a2f040b%2Fnuihmzm_processed.jpeg&w=3840&q=75)
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