In Rutherford's famous scattering experiments that led to the planetary model of the atom, alpha particles having charges of q = +2e and masses m= 6.64*1027 kg were fired toward a gold nucleus with charge Q = 79e. A lucky alpha particle, initially very far (assume ri = 00) from the gold nucleus, happened to be fired with an initial velocity vi = 2.00*10' m/s directed precisely toward the very center of the nucleus, as shown below. How close (find r) does the alpha particle get to the center of the gold nucleus before turning around? Assume the gold nucleus remains stationary. e = elementary charge = charge of the proton = 1.602·10-19 C. Because of the large charge of the nucleus and the large spatial distributions of electrons in atoms you may neglect any electrostatic interactions that the alpha particle has with any of the electrons of the gold atom on its way in. %3D %3D
In Rutherford's famous scattering experiments that led to the planetary model of the atom, alpha particles having charges of q = +2e and masses m= 6.64*1027 kg were fired toward a gold nucleus with charge Q = 79e. A lucky alpha particle, initially very far (assume ri = 00) from the gold nucleus, happened to be fired with an initial velocity vi = 2.00*10' m/s directed precisely toward the very center of the nucleus, as shown below. How close (find r) does the alpha particle get to the center of the gold nucleus before turning around? Assume the gold nucleus remains stationary. e = elementary charge = charge of the proton = 1.602·10-19 C. Because of the large charge of the nucleus and the large spatial distributions of electrons in atoms you may neglect any electrostatic interactions that the alpha particle has with any of the electrons of the gold atom on its way in. %3D %3D
Related questions
Question
100%
Please show all work and highlight your answers. Thank you!
Transcribed Image Text:In Rutherford's famous scattering experiments that led to the planetary model of the atom, alpha particles
having charges of q = +2e and masses m= 6.64*1027 kg were fired toward a gold nucleus with charge Q = 79e.
A lucky alpha particle, initially very far (assume ri = 00) from the gold nucleus, happened to be fired with an
initial velocity vi = 2.00*107 m/s directed precisely toward the very center of the nucleus, as shown below.
How close (find r) does the alpha particle get to the center of the gold nucleus before turning around? Assume
the gold nucleus remains stationary. e = elementary charge = charge of the proton = 1.602·10-19 C. Because of
the large charge of the nucleus and the large spatial distributions of electrons in atoms you may neglect any
electrostatic interactions that the alpha particle has with any of the electrons of the gold atom on its way in.
Vi
ri = 00
Expert Solution
Step 1
Given:
The initial velocity of the alpha particle, directed towards the center of the nucleus:
Mass of the alpha particle:
Charge of the alpha particle
Charge on the nucleus:
Step by step
Solved in 2 steps
