4. Use the "useful information" stated at the end of this problem to work out'the conversion from miles per hour (mi/hr) to meters per second (m/s). Please show your work. Distence Am 1 mi= 5280 ft Time Ahr = (60m Am 60sec 609 34.4m- 0.44204 m/s 360,000 S Useful information: 1 mi = 5,280 ft; 1 in = 2.54 cm; 1 m 100 cm; 12 in 1 ft; 60 s=1 min; 60 min 1 hr.

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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4. Use the "useful information" stated at the end of this problem to work out'the conversion from miles per
hour (mi/hr) to meters per second (m/s). Please show your work.
Distence
Am
12 x2.54mx-
1 mi= 52 80 ft
Time
609 34.4m= 0,44904 m/s
Ahr = (60m
%D
Am 60sec
3601000 s
Useful information:
5,280 ft; 1 in = 2.54 cm; 1 m =
100 cm; 12 in = 1 ft; 60 s-1 min; 60 min = 1 hr.
1 mi =
Transcribed Image Text:4. Use the "useful information" stated at the end of this problem to work out'the conversion from miles per hour (mi/hr) to meters per second (m/s). Please show your work. Distence Am 12 x2.54mx- 1 mi= 52 80 ft Time 609 34.4m= 0,44904 m/s Ahr = (60m %D Am 60sec 3601000 s Useful information: 5,280 ft; 1 in = 2.54 cm; 1 m = 100 cm; 12 in = 1 ft; 60 s-1 min; 60 min = 1 hr. 1 mi =
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