1) Use the data above to verify Kepler’s third Law, \( T^2 = \frac{4\pi^2}{GM} r^3 \) for the **orbit of the moon around the Earth**. You have multiple choices for \( T \), \( M \), and \( r \) in the table above. Explain why you choose the values you did from the table for this formula. Feel free to use the following data to complete your calculations:\( G = 6.67 \times 10^{-11} \, \frac{Nm^2}{kg^2} \)\( M_{\text{Sun}} = 1.989 \times 10^{30} \, kg \)**Moon:**\( T_{\text{moon around Earth}} = 27.3 \, \text{days} \)\( M_{\text{moon}} = 7.34 \times 10^{22} \, kg \)\( r_{\text{Moon to Earth}} = 3.84 \times 10^8 \, m \)\( r_{\text{Moon center to Moon surface}} = 1.74 \times 10^6 \, m \)**Earth:**\( T_{\text{Earth around Sun}} = 365.25 \, \text{days} \)\( M_{\text{Earth}} = 5.97 \times 10^{24} \, kg \)\( r_{\text{Earth to Moon}} = 3.84 \times 10^8 \, m \)\( r_{\text{Earth center to Earth surface}} = 6.37 \times 10^6 \, m \)

Answered: Image /qna-images/answer/496ee93a-d98c-498a-a434-3ccf6ccbbe60.jpg

1) Use the data above to verify Kepler's third Law, T² = r3 for the orbit of the moon GM around the Earth. You have multiple choices for T, M and r in the table above. Explain why you choose the values you did from the table for this formula.

1) Use the data above to verify Kepler's third Law, T² = r3 for the orbit of the moon GM around the Earth. You have multiple choices for T, M and r in the table above. Explain why you choose the values you did from the table for this formula.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

1) Use the data above to verify Kepler’s third Law, \( T^2 = \frac{4\pi^2}{GM} r^3 \) for the **orbit of the moon around the Earth**. You have multiple choices for \( T \), \( M \), and \( r \) in the table above. Explain why you choose the values you did from the table for this formula.

Feel free to use the following data to complete your calculations:

\( G = 6.67 \times 10^{-11} \, \frac{Nm^2}{kg^2} \)

\( M_{\text{Sun}} = 1.989 \times 10^{30} \, kg \)

**Moon:**

\( T_{\text{moon around Earth}} = 27.3 \, \text{days} \)

\( M_{\text{moon}} = 7.34 \times 10^{22} \, kg \)

\( r_{\text{Moon to Earth}} = 3.84 \times 10^8 \, m \)

\( r_{\text{Moon center to Moon surface}} = 1.74 \times 10^6 \, m \)

**Earth:**

\( T_{\text{Earth around Sun}} = 365.25 \, \text{days} \)

\( M_{\text{Earth}} = 5.97 \times 10^{24} \, kg \)

\( r_{\text{Earth to Moon}} = 3.84 \times 10^8 \, m \)

\( r_{\text{Earth center to Earth surface}} = 6.37 \times 10^6 \, m \)

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