1) Use the data above to verify Kepler's third Law, T² = r3 for the orbit of the moon GM around the Earth. You have multiple choices for T, M and r in the table above. Explain why you choose the values you did from the table for this formula.

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1) Use the data above to verify Kepler’s third Law, \( T^2 = \frac{4\pi^2}{GM} r^3 \) for the **orbit of the moon around the Earth**. You have multiple choices for \( T \), \( M \), and \( r \) in the table above. Explain why you choose the values you did from the table for this formula.
Transcribed Image Text:1) Use the data above to verify Kepler’s third Law, \( T^2 = \frac{4\pi^2}{GM} r^3 \) for the **orbit of the moon around the Earth**. You have multiple choices for \( T \), \( M \), and \( r \) in the table above. Explain why you choose the values you did from the table for this formula.
Feel free to use the following data to complete your calculations:

\( G = 6.67 \times 10^{-11} \, \frac{Nm^2}{kg^2} \)

\( M_{\text{Sun}} = 1.989 \times 10^{30} \, kg \)

**Moon:**

\( T_{\text{moon around Earth}} = 27.3 \, \text{days} \)

\( M_{\text{moon}} = 7.34 \times 10^{22} \, kg \)

\( r_{\text{Moon to Earth}} = 3.84 \times 10^8 \, m \)

\( r_{\text{Moon center to Moon surface}} = 1.74 \times 10^6 \, m \)

**Earth:**

\( T_{\text{Earth around Sun}} = 365.25 \, \text{days} \)

\( M_{\text{Earth}} = 5.97 \times 10^{24} \, kg \)

\( r_{\text{Earth to Moon}} = 3.84 \times 10^8 \, m \)

\( r_{\text{Earth center to Earth surface}} = 6.37 \times 10^6 \, m \)
Transcribed Image Text:Feel free to use the following data to complete your calculations: \( G = 6.67 \times 10^{-11} \, \frac{Nm^2}{kg^2} \) \( M_{\text{Sun}} = 1.989 \times 10^{30} \, kg \) **Moon:** \( T_{\text{moon around Earth}} = 27.3 \, \text{days} \) \( M_{\text{moon}} = 7.34 \times 10^{22} \, kg \) \( r_{\text{Moon to Earth}} = 3.84 \times 10^8 \, m \) \( r_{\text{Moon center to Moon surface}} = 1.74 \times 10^6 \, m \) **Earth:** \( T_{\text{Earth around Sun}} = 365.25 \, \text{days} \) \( M_{\text{Earth}} = 5.97 \times 10^{24} \, kg \) \( r_{\text{Earth to Moon}} = 3.84 \times 10^8 \, m \) \( r_{\text{Earth center to Earth surface}} = 6.37 \times 10^6 \, m \)
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