A 5μF capacitor with air between the metal plates is connected to a 12V battery. The battery is then removed, leaving the capacitor charged. (a) Calculate the charge on the capacitor. (b) The air between the plates is replaced by oil with er = 3. Find the new value of capacitances and the new potential difference between the plates.
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A 5μF capacitor with air between the metal plates is connected to a 12V battery. The battery is then
removed, leaving the capacitor charged.
(a) Calculate the charge on the capacitor.
(b) The air between the plates is replaced by oil with er = 3. Find the new value of capacitances and the new potential difference between the plates.
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But I found this equation for non-vacuum between the plate, I no need to deduct the Er of air 1.005?
Please see attachment.
by Bartleby ExpertIn part (b), do I need to take over the relative permittivity of AIR, that mean
C new = 3*5μF/1.0006 ?
by Bartleby Expert
