In outer space, high above the surface of Mars, a daring rescue is attempted as astronaut Mark Watney hurtles at 3 m/s relative to Commander Melissa Lewis who holds onto one end of an effectively massless tether. When Watney reaches the tether he is traveling perpendicularly to it and is 5 m from Lewis; each of them have a mass of 80 kg. 3 m/s A) In the C.O.M. reference frame for this system, what are the speeds of each astronaut when Watney reaches the tether? B) In this frame, what is the angular momentum of the two astronauts about the FC.O.M.? C) If Watney catches the tether, how much force must Lewis pull on it as they beginning orbiting their C.O.M.?
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- Two manned satellites approaching one another at a relative speed of 0.100 m/s intend to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. Assume that the positive direction is directed from the second satellite towards the first satellite. (a) Calculate the final velocity after docking, in the frame of reference in which the first satellite was originally at rest.m/s(b) What is the loss of kinetic energy in this inelastic collision?J(c) Repeat both parts, in the frame of reference in which the second satellite was originally at rest.final velocitym/sloss of kinetic energyJYou are the pilot of a spacecraft intended for travel at very high speeds. Before leaving you measure the spacecraft to be 31.4 m long and have a mass of 5.28 x 104 kg. During your travel, you pass a planet and exchange information with an observer on the planet. You are told that your spacecraft has been measured to be 28.6 m long. a. How fast is your spacecraft travelling with respect to the planet? b. You are told there is a nearby planet that is stationary with respect to the first planet. The observer on the first planet says it will take you 25 s to reach the nearby planet. How far away does your co-pilot on the spacecraft say the nearby planet is? c. How much energy was required to accelerate your spacecraft to this speed?Two manned satellites approaching one another, at a relative speed of 0.200 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. a. Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) m/s b. What is the loss of kinetic energy (in J) in this inelastic collision? J c. Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) m/sloss of kinetic energy (J) J Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.
- A spacecraft cruising in space at a constant velocity of 2000 ft/s has a mass of 25,000 lbm. To slow down the spacecraft, a solid fuel rocket is fired, and the combustion gases leave the rocket at a constant rate of 150 lbm/s at a velocity of 5000 ft/s in the same direction as the spacecraft for a period of 5 s. Assuming the mass of the spacecraft remains constant, determine (a) the deceleration of the spacecraft during this 5-s period, (b) the change of velocity of the spacecraft during this time period, and (c) the thrust exerted on the spacecraft.Kindly provide a CLEAR and COMPLETE solution. Please answer ASAP if possible, thanks.Two manned satellites approaching one another at a relative speed of 0.550 m/s intend to dock. The first has a mass of 4.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. Assume that the positive direction is directed from the second satellite towards the first satellite.(a) Calculate the final velocity after docking, in the frame of reference in which the first satellite was originally at rest. m/s(b) What is the loss of kinetic energy in this inelastic collision? J(c) Repeat both parts, in the frame of reference in which the second satellite was originally at rest.final velocity __________ m/sloss of kinetic energy _____________ J
- A man of mass 80 kg is standing stationary in the middle of a train carriage (see the figure below). The train is moving horizontally with a constant speed of 20 m/s (see the figure below), and the carriage is L=20 m long. Suddenly, the train starts to accelerate uniformly with a=2 m/s2 horizontally. a) Is the reference frame of the train now an inertial frame? Design an experiment that allows you to find out. b) Draw a free-body diagram of the man. Label the forces appropriately and explain their physical origin (one line each will suffice). c) If the coefficient of friction between the man's shoes and the `floor' of the train is μ=0.1, what is the maximum time that the man takes to hit the back of the train carriage? For simplicity, you can assume that the coefficient of static friction is the same as the coefficient of kinetic friction. Assume that there are no obstacles between the man and the back of the train. d) How does your answer change if the coefficient of…Two manned satellites approaching one another at a relative speed of 0.150M/S intend to dock. The first has a mass of 3.00×10^3 kg, the second a mass of 7.50 x 10^3 kg . Assume that the positive direction is directed from the second satellite towards the first satellite. (a) Calculate the final velocity after docking, in the frame of reference in which the first set a lot was originally at rest. m/s ? (b) what is the loss of kinetic energy in this inelastic collision? j ? (c) repeat both parts in the frame of reference in which the second satellite was originally at rest. Final velocity m/s ? loss of kinetic energy j ? explain why the change in velocity is different in the two frames, where areas the change in kinetic energy is the same in both. I used ^ to show exponentsTwo manned satellites approaching one another at a relative speed of 0.300 m/s intend to dock. The first has a mass of 4.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. Assume that the positive direction is directed from the second satellite towards the first satellite. (a) Calculate the final velocity after docking, in the frame of reference in which the first satellite was originally at rest. ..............m/s
- Which of the following are part of the first postulate of Einstein's Special Theory of Relativity? Time and weight are relative to the motion of the observer. All the laws of physics are the same in all inertial frames of reference. Absolute motion can always be detected. a I only b II only c III only d I, II, and III7) Two manned satellites approaching one another, at a relative speed of 0.550 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) _____m/s (b) What is the loss of kinetic energy (in J) in this inelastic collision? _____ J (c) Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) _____ m/s loss of kinetic energy (J) _____ J Explain in detail why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.7) Two manned satellites approaching one another, at a relative speed of 0.550 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) _____m/s (b) What is the loss of kinetic energy (in J) in this inelastic collision? _____ J (c) Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) _____ m/s loss of kinetic energy (J) _____ J Explain in detail why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.