Two manned satellites approaching one another, at a relative speed of 0.400 m/s, intending to dock. The first has a mass of 4.50 x 10 kg, and the second a mass of 7.50 x 10° kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answ m/s (b) What is the loss of kinetic energy (in ]) in this inelastic collision? (c) Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) m/s loss of kinetic energy (3) Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.

Two manned satellites approaching one another, at a relative speed of 0.400 m/s, intending to dock. The first has a mass of 4.50 x 10 kg, and the second a mass of 7.50 x 10° kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answ m/s (b) What is the loss of kinetic energy (in ]) in this inelastic collision? (c) Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) m/s loss of kinetic energy (3) Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Which of the following is the variation of acceleration due to gravity at a depth “d” below the earth’s surface? Let “R” be the radius of the earth and “M1” the mass of earth. (Assume the density of the earth to be constant) a) g = (G*M1)/(R – d) b) g = [(G*M1) x density]/d c) g = (G x M1/R3) / (R – d) d) g = (G x M1/R3) x (R – d)
Calculate the mass in kilograms of a 1.77 kg object when its velocity, relative to us, is each of the following values. (Notice the progression of these numbers toward the velocity of light, 3.00× 10° m s1) velocity = 3.07 x 107 ms1 m = i kg velocity = 2.75 × 10° ms1 kg m = i velocity = 2.98 x 10°ms1 kg m =
On Earth, a person has a weight of 520 N. What weight would the person have on Mars? Theradius of Mars is 53% of the radius of Earth, and its mass is 11% of the mass of Earth.
A spacecraft cruising in space at a constant velocity of 2000 ft/s has a mass of 25,000 lbm. To slow down the spacecraft, a solid fuel rocket is fired, and the combustion gases leave the rocket at a constant rate of 150 lbm/s at a velocity of 5000 ft/s in the same direction as the spacecraft for a period of 5 s. Assuming the mass of the spacecraft remains constant, determine (a) the deceleration of the spacecraft during this 5-s period, (b) the change of velocity of the spacecraft during this time period, and (c) the thrust exerted on the spacecraft.
[a] An asteroid with mass X kilograms (kg) is moving eastward at Y meters per second (m/s) collides another asteroid, also with mass X kg, which is moving northward at Z m/s. They stick together and keep moving through space. Draw a diagram of this interaction, labeling all the relevant objects, quantities, and velocity vectors before and after the collision. [b] What is the velocity (magnitude and direction) of the two asteroids after they collide? Your answer should be significant to two digits.
To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 kg person, the mass of the upper leg is 8.60 kg, while that of the lower leg (including the foot) is 5.25 kg. Find the location of the center of mass of this leg, relative to the hip joint, if it is (a) fully extended, and (b) bent at the knee to form a right angle with the upper leg.
The following equation describes the motion of a rocket that is expelling a total mass M of fuel at a rateα = -dm/dt:dv/dt = uα/(M-αt),where u is the speed the fuel is ejected, v is the velocity of the rocket in the x-direction, and t is time. Assume the velocity at t = 0 is v(0) = v0, and that M, and u are constants. The burn rate is proportional to the mass of the rocket, as follows:α = -βm,where m is the current mass of the rocket (which is therefore time-dependent). This means that as less fuel is available to burn, then the fuel is burned at a lower rate. Write an expression for the mass of the fuel as a function of time. Now, write an expression for the velocity as a function of time for the rocket. A particular rocket burns fuel at a rate proportional to the mass of the fuel with the constant of proportionality being 6.4 1/s. The propellant speed is 5.1 m/s. The total mass of fuel is 136.4 kg. What is the speed, in meters per second, of the rocket at t = 2.7 s?
Q.2)
The robot moves the particle A (mass M) in the vertical plane using polar coordinate formulas r(t) = 1,2-0,6sin(2πt) [m] θ(t) = 0,5-1,5cos(2πt) [rad] in accordance with. Determine the acceleration of the body in the r-direction [m / s2] at time t0 = 1.9 s Use units [m/s2] GIVE ANSWER TO THREE DECIMALS
The following data were collected for the distance traveled versus time for a rocket. What could have been the distance traveled by the rocket at t=150, given xi=100 using first derivative four point central? Kindly answer it fast. Thank you