In order to get the step 4 the full yellow paper will be the guide to find the step 4. STEP 1: Current Loops STEP 2: Remove Integrals STEP 3: Simplify STEP 4: ? Note: THE YELLOW FULL PAPER HAVE A DIFFERENT GIVEN YOU WILL JUST USE THIS AS A GUIDE OR REFERENCES HOW TO SOLVE THE STEP 4:
In order to get the step 4 the full yellow paper will be the guide to find the step 4. STEP 1: Current Loops STEP 2: Remove Integrals STEP 3: Simplify STEP 4: ? Note: THE YELLOW FULL PAPER HAVE A DIFFERENT GIVEN YOU WILL JUST USE THIS AS A GUIDE OR REFERENCES HOW TO SOLVE THE STEP 4:
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
In order to get the step 4 the full yellow paper will be the guide to find the step 4.
STEP 1: Current Loops
STEP 2: Remove Integrals
STEP 3: Simplify
STEP 4: ?
Note: THE YELLOW FULL PAPER HAVE A DIFFERENT GIVEN YOU WILL JUST USE THIS AS A GUIDE OR REFERENCES HOW TO SOLVE THE STEP 4:
![IN ORDER TO GET THE STEP 4.
(HERE'S A HINT)
Step 4
80+の-R i D the )i=0)0
Gx )oxt 4y-し
5 (4tS)
at25
-317-
2564
* DCt)
31
不tUす。U% t08
in
auet)
O* +la n+3
Step4
3Dの, -3。
(20 47 30, +(80+8]ig=0]
%3D
90
=ーのve)
= -3クv)
%3D
こ0
(-1603-310 -a47ia = -30 uCt)
%3D
-3DV(4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b011a6a-089c-4042-a8e4-44afadcb759f%2Ff3767670-ee5a-4d94-9263-01c1a9a5e8e1%2F8862r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:IN ORDER TO GET THE STEP 4.
(HERE'S A HINT)
Step 4
80+の-R i D the )i=0)0
Gx )oxt 4y-し
5 (4tS)
at25
-317-
2564
* DCt)
31
不tUす。U% t08
in
auet)
O* +la n+3
Step4
3Dの, -3。
(20 47 30, +(80+8]ig=0]
%3D
90
=ーのve)
= -3クv)
%3D
こ0
(-1603-310 -a47ia = -30 uCt)
%3D
-3DV(4)
![72
1/5F
|54 IN3H
The
given circuit
Step!:
lurrent loops
SF
7n
L di
at
iこ cdve
dt
write kVL in loop I
7i, +5 Ci, -iz)
12 i, - 5iz
VC) =
viり -
>
write
KVL in lop 2
0= 5(i2 -i,) +Siz at -
V5
véSiz at + 3 die
dt
Step 2:-
Remove
Integrals
Diffren hute esuiton @
with vespect to t°
o-d$ Cie-i)s + 5 i2 +3 di.
dt
step 3:
Simplity
V cD = 12 i, - 5i2
5 diz
dt
5 di,
+ 5i2 +3 d?iz
dt
dtz
- 5D i, +[30+5 D +5] iz
D= d
dt
STEP 4: ?
such as resistors, capacitors, and transistors.
Resistor
Capacitor
Inductor
VR = iRR
Jap
ic = C-
dt
%3D
di.
%3D
7 = la
dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b011a6a-089c-4042-a8e4-44afadcb759f%2Ff3767670-ee5a-4d94-9263-01c1a9a5e8e1%2Fjmrtyx_processed.jpeg&w=3840&q=75)
Transcribed Image Text:72
1/5F
|54 IN3H
The
given circuit
Step!:
lurrent loops
SF
7n
L di
at
iこ cdve
dt
write kVL in loop I
7i, +5 Ci, -iz)
12 i, - 5iz
VC) =
viり -
>
write
KVL in lop 2
0= 5(i2 -i,) +Siz at -
V5
véSiz at + 3 die
dt
Step 2:-
Remove
Integrals
Diffren hute esuiton @
with vespect to t°
o-d$ Cie-i)s + 5 i2 +3 di.
dt
step 3:
Simplity
V cD = 12 i, - 5i2
5 diz
dt
5 di,
+ 5i2 +3 d?iz
dt
dtz
- 5D i, +[30+5 D +5] iz
D= d
dt
STEP 4: ?
such as resistors, capacitors, and transistors.
Resistor
Capacitor
Inductor
VR = iRR
Jap
ic = C-
dt
%3D
di.
%3D
7 = la
dt
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