· In general, under room temperature, which of the following type(s) of solid(s) would not dissolve in any kind of a solvent? a) network covalent b) ionic or polar molecular c) ionic d) metallic e) polar molecular If at a particular temperature the solubility of oxygen gas in water is 0.771 g/L at an oxygen pressure of around 19.2 atm. What is the Henry's law constant for 02 (in units of L· atm/mol)? 0 = 16.00 amu

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### Solubility and Henry's Law

**Question:**
In general, under room temperature, which of the following type(s) of solid(s) would not dissolve in any kind of a solvent?

a) network covalent  
b) ionic or polar molecular  
c) ionic  
d) metallic  
e) polar molecular  

**Explanation:**
This question probes the solubility characteristics of different types of solids when exposed to solvents under standard room temperature conditions. Understanding why a particular type of solid would or would not dissolve in solvents involves knowledge of intermolecular forces and bonding:

- **Network Covalent**: Typically insoluble in solvents due to strong covalent bonds throughout the entire structure.
- **Ionic or Polar Molecular**: Generally soluble in polar solvents due to ionic/polar interactions.
- **Ionic**: Soluble in polar solvents (e.g., water) due to ion-dipole interactions.
- **Metallic**: Typically insoluble; metallic bonds are not easily disrupted by solvents.
- **Polar Molecular**: Soluble in polar solvents; like dissolves like principle.

**Question:**
If at a particular temperature the solubility of oxygen gas in water is 0.771 g/L at an oxygen pressure of around 19.2 atm. What is the Henry's law constant for \( O_{2} \) (in units of L ⋅ atm/mol)?

Given:
\[ O = 16.00 \, \text{amu} \]

**Explanation:**
To determine Henry's law constant (\( k_H \)), the solubility of the gas in the solvent, and the partial pressure of the gas above the solvent are used. Henry's law is described by the equation: 
\[ C = k_H \cdot P \]
where:
- \( C \) is the concentration of the dissolved gas (solubility),
- \( k_H \) is the Henry's law constant,
- \( P \) is the partial pressure of the gas.

Given data:
- Solubility \( C = 0.771 \, \text{g/L} \)
- Partial pressure \( P = 19.2 \, \text{atm} \)
- Molecular weight of \( O_{2} \) = \( 2 \times 16.00 \, \text{amu} = 32.00 \, \text{g/mol} \)

First, convert the sol
Transcribed Image Text:### Solubility and Henry's Law **Question:** In general, under room temperature, which of the following type(s) of solid(s) would not dissolve in any kind of a solvent? a) network covalent b) ionic or polar molecular c) ionic d) metallic e) polar molecular **Explanation:** This question probes the solubility characteristics of different types of solids when exposed to solvents under standard room temperature conditions. Understanding why a particular type of solid would or would not dissolve in solvents involves knowledge of intermolecular forces and bonding: - **Network Covalent**: Typically insoluble in solvents due to strong covalent bonds throughout the entire structure. - **Ionic or Polar Molecular**: Generally soluble in polar solvents due to ionic/polar interactions. - **Ionic**: Soluble in polar solvents (e.g., water) due to ion-dipole interactions. - **Metallic**: Typically insoluble; metallic bonds are not easily disrupted by solvents. - **Polar Molecular**: Soluble in polar solvents; like dissolves like principle. **Question:** If at a particular temperature the solubility of oxygen gas in water is 0.771 g/L at an oxygen pressure of around 19.2 atm. What is the Henry's law constant for \( O_{2} \) (in units of L ⋅ atm/mol)? Given: \[ O = 16.00 \, \text{amu} \] **Explanation:** To determine Henry's law constant (\( k_H \)), the solubility of the gas in the solvent, and the partial pressure of the gas above the solvent are used. Henry's law is described by the equation: \[ C = k_H \cdot P \] where: - \( C \) is the concentration of the dissolved gas (solubility), - \( k_H \) is the Henry's law constant, - \( P \) is the partial pressure of the gas. Given data: - Solubility \( C = 0.771 \, \text{g/L} \) - Partial pressure \( P = 19.2 \, \text{atm} \) - Molecular weight of \( O_{2} \) = \( 2 \times 16.00 \, \text{amu} = 32.00 \, \text{g/mol} \) First, convert the sol
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