A certain substance X condenses at a temperature of 90.5 °C. But if a 600. g sample of X is prepared with 35.3 g of ureaof X.sample is found to have a condensation point of 91.2 °C instead. Calculate the molal boiling point elevation constant KRound your answer to 1 significant digit.- 1°C-mol .kg0x10X((NH₂)₂CO) dissolved in it, the

Answered: Image /qna-images/answer/4e540006-5d4b-475a-8bf3-5fcb2d31a120.jpg

Answered: A certain substance X condenses at a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

A certain substance X condenses at a temperature of 90.5 °C. But if a 600. g sample of X is prepared with 35.3 g of urea
of X.
sample is found to have a condensation point of 91.2 °C instead. Calculate the molal boiling point elevation constant K
Round your answer to 1 significant digit.
- 1
°C-mol .kg
0
x10
X
((NH₂)₂CO) dissolved in it, the

Expert Solution

Step 1: Determine the molar boiling point elevation constant from the given data:

$G i v e n comma T h e space c o n d e n s a t i o n space t e m p e r a t u r e space o f space s u b s tan c e space X space equals space 90.5 space degree C T h e space c o n d e n s a t i o n space t e p e r a t u r e space o f space s o l u t i o n space equals space 91.2 space degree C m a s s space o f space X space equals space 600. space g m a s s space o f space u r e a space left parenthesis space left parenthesis space N H subscript 2 right parenthesis subscript 2 C O space right parenthesis space equals space 35.3 space g bold italic D bold italic e bold italic f bold italic i bold italic n bold italic i bold italic t bold italic i bold italic o bold italic n bold colon T h e space b o i l i n g space p o i n t space i s space a space t e m p e r a t u r e space a t space w h i c h space t h e space l i q u i d space i s space c o n v e r t e d space i n t o space t h e space g a s e o u s space p h a s e space a n d C o n d e n s a t i o n space p o i n t space i s space a space t e m p e r a t u r e space a t space w h i c h space g a s space c h a n g e s space t o space l i q u i d. B o t h space t h e s e space p r o c e s s e s space o c c u r space a t space t h e space bold italic s bold italic a bold italic m bold italic e bold space bold italic t bold italic e bold italic m bold italic p bold italic e bold italic r bold italic a bold italic t bold italic u bold italic r bold italic e bold space p o i n t space h e n c e space t h e space b o i l i n g space p o i n t space a n d space c o n d e n s a t i o n space p o i n t space a r e space t h e space s a m e.$

Step by step

Solved in 4 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions