In Figure, a block with mass m = 1 kg is released from height h1= 12 m. Its path is without friction until it reaches the path with first length d1= 2 m, where the friction force between B and C is fs1= 8 N, and until it reaches the path, where the friction force between E and F is fs2= 6 N. The height is h2=1 m, and second horizontal length is d2= 1 m. The block continues its motion after the point F. (a) Find the velocity at the point A. (b) Find the velocity at the point D. (c) Find the height h if the velocity of m is vF= 8 m/s at the point F.(sin60=0.86 g=9.8 m/s2)

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Chapter1: Units, Trigonometry. And Vectors
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In Figure, a block with mass m = 1 kg is released from height h1= 12 m. Its path is without friction until it reaches the path with first length d1= 2 m, where the friction force between B and C is fs1= 8 N, and until it reaches the path, where the friction force between E and F is fs2= 6 N. The height is h2=1 m, and second horizontal length is d2= 1 m. The block continues its motion after the point F.
(a) Find the velocity at the point A.
(b) Find the velocity at the point D.
(c) Find the height h if the velocity of m is vF= 8 m/s at the point F.(sin60=0.86 g=9.8 m/s2)

m
F
=1 m
h
D
->
h, = 12 m
60°
E
d,=2 m
h,=1 m
А В
Transcribed Image Text:m F =1 m h D -> h, = 12 m 60° E d,=2 m h,=1 m А В
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