An object of mass 380 kg is sliding on a track. From A to B, the track is frictionless. From B to C the coefficient of kinetic friction = 0.3. The velocity of the object at point A is < 10, 0, 0> m/s. It took the object 15 s to go from A to B. 1) 2) 3) A Friction = 0 UB=< 1AFI= B Friction #0 Knowing that the net force is zero on track AB. What is the velocity of the object at point B. m C > m/s In the formula-sheet provided which equation can be used to calculate the length of the track AB. The length of the track AB +

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Chapter1: Units, Trigonometry. And Vectors
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An object of mass 380 kg is sliding on a track. From A to B, the track is frictionless. From B to C the coefficient of kinetic friction =
0.3. The velocity of the object at point A is < 10,0,0> m/s. It took the object 15 s to go from A to B.
1)
2)
3)
4)
A
5)
6)
Friction = 0
UB=<
1AFI=
|FN|=
|fr|=
At=
Friction #0
Knowing that the net force is zero on track AB. What is the velocity of the object at point B.
> m/s
m
B
In the formula-sheet provided which equation can be used to calculate the length of the track AB,
The length of the track AB
C
The magnitude of the normal force on track BC
N
S
the magnitude of the kinetic friction force on track BC
N
How long will it take for the object to stop?
O
Transcribed Image Text:An object of mass 380 kg is sliding on a track. From A to B, the track is frictionless. From B to C the coefficient of kinetic friction = 0.3. The velocity of the object at point A is < 10,0,0> m/s. It took the object 15 s to go from A to B. 1) 2) 3) 4) A 5) 6) Friction = 0 UB=< 1AFI= |FN|= |fr|= At= Friction #0 Knowing that the net force is zero on track AB. What is the velocity of the object at point B. > m/s m B In the formula-sheet provided which equation can be used to calculate the length of the track AB, The length of the track AB C The magnitude of the normal force on track BC N S the magnitude of the kinetic friction force on track BC N How long will it take for the object to stop? O
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