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In Exercises 1-20 solve the initial value problem. Where indicated by C/G, graph the solution. 1. y' + 3y + 2y = 6e²t +28(t − 1), y(0) = 2, y'(0) = -6 -t 2. |C/G| y" + y − 2y = −10e¯t + 58(t-1), y(0)=7, y'(0) = 2 3. y4y= 2e-t +58(t-1), y(0) = -1, C/G| y" + y = sin 3t+28(t - π/2), 4. 5. y(0) = 0, y + 4y = 4 + 8(t-3π), yy=8+28(t− 2), 6. y(0) = -1, 7. y' + y = et + 38(t-6), 8. 9. y(0) = 1, y'(0) = 1 y'(0) = 1 y(0) = -1, y" + 4y = 8e²t + 8(t - π/2), y(0) = 8, y'(0) = 4 C/Gy'" + 3y + 2y = 1+8(t−1), y(0) y'(0) y' (0) = 0 y'(0) = = -1 = 1, y'(0) = −1 = -9

In Exercises 1-20 solve the initial value problem. Where indicated by C/G, graph the solution. 1. y' + 3y + 2y = 6e²t +28(t − 1), y(0) = 2, y'(0) = -6 -t 2. |C/G| y" + y − 2y = −10e¯t + 58(t-1), y(0)=7, y'(0) = 2 3. y4y= 2e-t +58(t-1), y(0) = -1, C/G| y" + y = sin 3t+28(t - π/2), 4. 5. y(0) = 0, y + 4y = 4 + 8(t-3π), yy=8+28(t− 2), 6. y(0) = -1, 7. y' + y = et + 38(t-6), 8. 9. y(0) = 1, y'(0) = 1 y'(0) = 1 y(0) = -1, y" + 4y = 8e²t + 8(t - π/2), y(0) = 8, y'(0) = 4 C/Gy'" + 3y + 2y = 1+8(t−1), y(0) y'(0) y' (0) = 0 y'(0) = = -1 = 1, y'(0) = −1 = -9

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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In Exercises 1-20 solve the initial value problem. Where indicated by C/G, graph the solution. y" + 3y + 2y = 6e²t + 28(t − 1), y(0) = 2, y'(0) = −6 -6 1. 2. C/Gy' + y' - 2y = −10e-t +58(t-1), 3. y4y = 2e¯t +58(t−1), y(0) = −1, C/Gy" + y = sin 3t+26(t — π/2), y" + 4y = 4 + 8(t - 3π), y(0) = 0, yy=8+28(t− 2), y(0) = −1, 4. 5. 6. 7. y"+y' = et + 38(t− 6), 8. 9. y(0) = −1, y(0) = 7, y'(0) = −9 y'(0) = 2 y(0) = 1, y'(0) = −1 y'(0) = 1 y'(0) = 1 y'(0) = 4 y" + 4y = 8e²t + 8(t-π/2), y(0) = 8, y'(0) = 0 C/G y + 3y + 2y = 1+8(t−1), y(0) = 1, y'(0) = −1
Transcribed Image Text:In Exercises 1-20 solve the initial value problem. Where indicated by C/G, graph the solution. y" + 3y + 2y = 6e²t + 28(t − 1), y(0) = 2, y'(0) = −6 -6 1. 2. C/Gy' + y' - 2y = −10e-t +58(t-1), 3. y4y = 2e¯t +58(t−1), y(0) = −1, C/Gy" + y = sin 3t+26(t — π/2), y" + 4y = 4 + 8(t - 3π), y(0) = 0, yy=8+28(t− 2), y(0) = −1, 4. 5. 6. 7. y"+y' = et + 38(t− 6), 8. 9. y(0) = −1, y(0) = 7, y'(0) = −9 y'(0) = 2 y(0) = 1, y'(0) = −1 y'(0) = 1 y'(0) = 1 y'(0) = 4 y" + 4y = 8e²t + 8(t-π/2), y(0) = 8, y'(0) = 0 C/G y + 3y + 2y = 1+8(t−1), y(0) = 1, y'(0) = −1
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