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In Designing a lag compensator for the shown system, the only thing left is to determine the gain Ke. Take the closed-loop poles as (s= -1.21 j0.4). Determine Ke. R(s) C(s) Select one: O a. 0.23 O b. 0.75 O c. 1 O d. 0.85 Oe. -1 Ke S+0.5 s+0.05 lag compensator 1 s(s+1) plant 4

In Designing a lag compensator for the shown system, the only thing left is to determine the gain Ke. Take the closed-loop poles as (s= -1.21 j0.4). Determine Ke. R(s) C(s) Select one: O a. 0.23 O b. 0.75 O c. 1 O d. 0.85 Oe. -1 Ke S+0.5 s+0.05 lag compensator 1 s(s+1) plant 4

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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In Designing a lag compensator for the shown system, the only thing left is to determine the gain Kc. Take the closed-loop poles as (s= -1.2 j0.4). Determine Ke. R(s) C(s) 71 s(s+1) plant Select one: Oa. 0.23. O b. 0.75 Oc 1 O d. 0.85 O e. -1 S+0.5 Ke s+0.05 lag compensator
Transcribed Image Text:In Designing a lag compensator for the shown system, the only thing left is to determine the gain Kc. Take the closed-loop poles as (s= -1.2 j0.4). Determine Ke. R(s) C(s) 71 s(s+1) plant Select one: Oa. 0.23. O b. 0.75 Oc 1 O d. 0.85 O e. -1 S+0.5 Ke s+0.05 lag compensator
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