Determine the capacitance of each of the capacitors in the Figure below. Take: Er1 = 4, Er2 = 6, d=5 mm, S = 30 cm². 81 d/2 d/2 w/2 w/2 (a) Example (a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can be treated as consisting of two capacitors C, and C₂ in series ,,S 26,S 20,0,S +
Determine the capacitance of each of the capacitors in the Figure below. Take: Er1 = 4, Er2 = 6, d=5 mm, S = 30 cm². 81 d/2 d/2 w/2 w/2 (a) Example (a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can be treated as consisting of two capacitors C, and C₂ in series ,,S 26,S 20,0,S +
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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explain calculations please

Transcribed Image Text:Determine the capacitance of each of the capacitors in the Figure below. Take:
Er1 = 4, &r2 = 6, d= 5 mm, S = 30 cm².
Erl
d/2
Erl
d/2
w/2
(b)
Example
(a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can
be treated as consisting of two capacitors C, and C₂ in series
26,S
26,88
C₁ =
66,
d/2
C₂=
The total capacitor C is given by
2ES (₁²₂)
d B₂₁ +8₂
10~* 30 × 10 4 Xô
36 5 X 10
C-
10
C = 25.46 pl
82
-
(a)
C₂C₂
G₁+ C₂
= 2-
w/2
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