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Determine the capacitance of each of the capacitors in the Figure below. Take: Er1 = 4, Er2 = 6, d=5 mm, S = 30 cm². 81 d/2 d/2 w/2 w/2 (a) Example (a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can be treated as consisting of two capacitors C, and C₂ in series ,,S 26,S 20,0,S +

Determine the capacitance of each of the capacitors in the Figure below. Take: Er1 = 4, Er2 = 6, d=5 mm, S = 30 cm². 81 d/2 d/2 w/2 w/2 (a) Example (a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can be treated as consisting of two capacitors C, and C₂ in series ,,S 26,S 20,0,S +

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Determine the capacitance of each of the capacitors in the Figure below. Take: Er1 = 4, &r2 = 6, d= 5 mm, S = 30 cm². Erl d/2 Erl d/2 w/2 (b) Example (a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can be treated as consisting of two capacitors C, and C₂ in series 26,S 26,88 C₁ = 66, d/2 C₂= The total capacitor C is given by 2ES (₁²₂) d B₂₁ +8₂ 10~* 30 × 10 4 Xô 36 5 X 10 C- 10 C = 25.46 pl 82 - (a) C₂C₂ G₁+ C₂ = 2- w/2
Transcribed Image Text:Determine the capacitance of each of the capacitors in the Figure below. Take: Er1 = 4, &r2 = 6, d= 5 mm, S = 30 cm². Erl d/2 Erl d/2 w/2 (b) Example (a) Since D and E are normal to the dielectric interface, the capacitor in Figure 6.20(a) can be treated as consisting of two capacitors C, and C₂ in series 26,S 26,88 C₁ = 66, d/2 C₂= The total capacitor C is given by 2ES (₁²₂) d B₂₁ +8₂ 10~* 30 × 10 4 Xô 36 5 X 10 C- 10 C = 25.46 pl 82 - (a) C₂C₂ G₁+ C₂ = 2- w/2
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