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In cgs units, the Coulomb Force Law is written as F = 9192. In other words -
r2
Απ εο
is chosen to
have a value of 1. a) Hence what is the value of μo? b) Re-write Maxwell's equations in
differential form using cgs units.

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F=0.8975r^-2.00 And re-writing it as: (4)F=0.8975/r^-2.00 We can now compare it with Coulomb’s equation: (1)F=K|q1q2|/r^2 So, comparing these equations (4) and (1) we realize that: k=|q1q2|=0.8975 Plugging in values for charges: q1 = -10µC, and q2 = 10µC, isolating k (Coulomb’s constant), and recalling that 1µC = 10-6 C, we get: k|-10µC*10µC|=0.8975 k=0.8934/|-10µC*10µC|= 0.8934/10*10^-6C*10*10^-6C (3) Use this Example calculation above, and the trendline equation (3) coefficients that you have obtained on your graph, to find k. Show your work below. Be careful with powers of ten. k= 0.8975/|-10µC*10µC|= 0.8975/10*10^-6C*10*10^-6C = (5) Now, important part in reporting the answer is properly showing its units. To derive the SI units for Coulomb’s constant k, let’s look again at the equation (1), and re-write it as: k=F*r^2/|q1q2| (6) Recalling the units for all parameters in this equation: Force, F – Newtons, [N] Distance, r –…