In April 2010,45%of the unemployed had been out of work longer than six months. Policy makers felt that this percentage declined during 2010 as the job market improved. To test this theory, a random sample of200unemployed people wasselected, and it was found that67had been out of work for more than six months. Usingα=0.10,answer parts a through c below. **Hypothesis Testing Example**In April 2010, 45% of the unemployed population had been out of work for longer than six months. Policy makers speculated that this percentage declined during 2010 as the job market improved. To evaluate this hypothesis, a random sample of 200 unemployed individuals was selected, revealing that 67 had been out of work for more than six months. Using a significance level (\(\alpha\)) of 0.10, parts a through c provide insight into this matter.**a. Determining Proportional Changes in Long-term Unemployment**What conclusions can be drawn regarding the proportion of the unemployed who have been out of work for over six months?**Task: Determine the Null and Alternative Hypotheses**Select the correct answer below:- **A.** \( H_0: p > 0.45 \) \( H_1: p \leq 0.45 \)- **B.** \( H_0: p \leq 0.45 \) \( H_1: p > 0.45 \)- **C.** \( H_0: p \geq 0.45 \) \( H_1: p < 0.45 \)- **D.** \( H_0: p = 0.45 \) \( H_1: p \neq 0.45 \)

In April 2010, 45% of the unemployed had been out of work longer than six months. Policy makers felt that this percentage declined during 2010 as the job market improved. To test this theory, a random sample of 200 unemployed people was selected, and it was found that 67 had been out of work for more than six months. Using a = 0.10, answer parts a through c below. a. What conclusions can be drawn about the proportion of the unemployed who have been out of work for more than six months? Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: p>0.45 H: ps0.45 O B. Ho: ps0.45 H,:p>0.45 OC. Ho: p20.45 O D. Ho: p=0.45 H:p#0.45 H,:p<0.45

In April 2010, 45% of the unemployed had been out of work longer than six months. Policy makers felt that this percentage declined during 2010 as the job market improved. To test this theory, a random sample of 200 unemployed people was selected, and it was found that 67 had been out of work for more than six months. Using a = 0.10, answer parts a through c below. a. What conclusions can be drawn about the proportion of the unemployed who have been out of work for more than six months? Determine the null and alternative hypotheses. Choose the correct answer below. O A. Ho: p>0.45 H: ps0.45 O B. Ho: ps0.45 H,:p>0.45 OC. Ho: p20.45 O D. Ho: p=0.45 H:p#0.45 H,:p<0.45

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question Two.
A report by the New York Times in 2022 indicated that, on average, a married woman in the United States goes out with her female friends an average of 5.7 times peryear. A student at Century College conducts a study of her own by randomly surveying married women in White Bear Lake and obtained this data for the number of times in a year: 3 1 1 3 7 2 9 4 6 4 3 8 0 5 6 4 0 1 3 0 Use your calculator to determine the mean and standard deviation for this sample. Then, at the level of significance, Test the claim that married women in White Bear Lake, on average, go out with their female friends less than the overall national average. Be complete, show every step including hypotheses, a labelled graph, and clearly state the final result. Do not use the P-value method. Explain what the final result means in the context of this problem.
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.1 4.7 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference ?1 − ?2. Round the test statistic and critical value to three decimal places.) test statistic critical value Find (or estimate) the P-value. A. P-value > 0.250 B. 0.125 < P-value < 0.250 C. 0.050 < P-value < 0.125 D. 0.025 < P-value <…
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.9 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.1 4.5 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference ?1 − ?2. Round the test statistic and critical value to three decimal places.)
Use the following data to answer question 13 - 16. Breast cancer is one of the leading causes of death in women prior to age fifty. A study of the effectiveness of regular breast self-examination (BSE) reported in the American Journal of Public Health found that 23 of 53 women who discovered a tumor through BSE had a tumor in an early stage. Of 178 women who discovered a tumor by accident, 48 had a tumor in an early stage. Let P1 and P2 denote the proportion of women who detected early stage tumor through BSE and by accident, and let P1 and P2 denote the corresponding estimates.
The medical community unanimously agrees on the health benefits of regular exercise, but are adults listening? During each of the past 15 years, a polling organization has surveyed americans about their exercise habits. In the most recent of these polls, slightly over half of all American adults reported that they exercise for 30 or more minutes at least three times per week. The following data show the percentages of adults who reported that they exercise for 30 or more minutes at least three times per week during each of the 15 years of this study. Year Percentage of Adults Who Exercise 30 or more minutes at least three times per week 1 41.1 2 45 3 47.2 4 45.6 5 46.5 6 44.4 7 47.7 8 49.9 9 48 10 49 11 50 12 52.2 13 50.7 14 54.5 15 52.3 use simple linear regression to find the parameters for the line that minimizes MSE for this time series. Do not round your interim computations and…
Only the question 5 and 6 need to be resolved. Others have been reaolved already. Question: sample of 15, 10 years old children was taken to study whether watching television reduces the amount of physical exercise, causing weight gains. The number of kilograms each child was overweight by was recorded (a negative number indicates the child is underweight). In addition, the number of hours of television viewing per week was also recorded. These data are listed in the table below. Television(hours) 42 34 25 35 37 38 31 33 19 29 38 28 29 36 18 Overweight (Kg) 8 3 0 0 6 6 3 3 -4 4 4 2 1 6 -3 Use an appropriate plot to investigate the relationship between Television(hours) and Overweight (KG). Briefly explain the selection of each variable on the X and Y axes and why? Calculate and interpret the coefficient of correlation (r) between Television(hours) and Overweight (KG).…
A researcher wants to know whether children with ADHD tend to watch more TV than children who are not diagnosed with the disorder. To examine this, a researcher obtains a sample of n = 36 children (ages 8 to 12 years) who have been diagnosed with ADHD. Each child is asked to keep a journal recording how much time each day is spent watching TV. The average for the sample is M = 4.9 hours/day. Assume that the average TV-watching time for the general population of 8-to-12-year-old children is µ = 4.1 hours/day with σ = 1.8. Is ADHD in children associated with an increased amount of TV-watching?
In a population-based cohort study, an entire community was interviewed regarding smoking habits and then followed for one year. Upon ascertainment of all lung cancer deaths, the investigator obtained the following data: Number of Individuals Lung Cancer Deaths Smokers 24,500 15 Nonsmokers 10,500 2 Calculate the risk difference per 100,000 per year. Round to the tenth decima
Q. 4 Surgery was performed on 492 patients in the Anywhere Health Care Facility during March, and 27 of those patients died within 10 days of surgery. Find Postoperative death rate.
Please review Section 11.1. Are you an impulse shopper? A survey of 500 grocery shoppers indicated that 16% of males and 42% of females make an impulse purchase every time they shop. Assume that the survey consisted of 250 males and 250 females. Let group 1 be the males and let group 2 be the females.alpha = 0.05H0: pie = pieH1: pie not = pie Calculate the test statistic: (Round to three decimal places as needed.)Determine the critical value: (Round to three decimal places as needed.)State the Conclusion:
A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.9 4.1 4.5 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference ?1 − ?2. Round the test statistic and critical value to three decimal places.) test statistic critical value