In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, e"max, to the maximum angular velocity, e'max, is 21t s^(-1). What is the time needed for the pendulum to complete two oscillations? 2 sec 0.5 sec 0.25 sec 4 sec 1 sec
In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, e"max, to the maximum angular velocity, e'max, is 21t s^(-1). What is the time needed for the pendulum to complete two oscillations? 2 sec 0.5 sec 0.25 sec 4 sec 1 sec
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15 MCQS
In an oscillatory motion of a simple
pendulum, the ratio of the maximum
angular acceleration, e"max, to the
maximum angular velocity, O'max, is 21t
s^(-1). What is the time needed for the
pendulum to complete two
oscillations?
2 sec
0.5 sec
0.25 sec
4 sec
1 sec
A traveling wave on a taut string with a
tension force T is given by the wave
function: y(x,t) = 0.1sin(2rtx-300t),
where x and y are in meters and t is in
seconds The linear mass density of the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc9a106ef-b522-4cd8-853e-16e8c052e618%2F045cb1f1-55fc-4d1f-9103-b2b3f8d12f85%2Fjv1jbeb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4:32
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15 MCQS
In an oscillatory motion of a simple
pendulum, the ratio of the maximum
angular acceleration, e"max, to the
maximum angular velocity, O'max, is 21t
s^(-1). What is the time needed for the
pendulum to complete two
oscillations?
2 sec
0.5 sec
0.25 sec
4 sec
1 sec
A traveling wave on a taut string with a
tension force T is given by the wave
function: y(x,t) = 0.1sin(2rtx-300t),
where x and y are in meters and t is in
seconds The linear mass density of the
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