The piston inside a car cylinder osscilates up and down with Simple Harmonic Motion at 5400 cylces per minute. It travels upwards through a distance of 24cm and downwards through 24cm each cycle. What is the amplitude of the SHM? (m) Answer: 0.24 x What is the angular frequency of the motion? (rad/s) Answer: 565.5 The total distance moved is 24cm. The equillibrium position is in the middle. Hence the amplitude is equal to half of 24 cm, 0.12m. x Answer: 135.72 What is the maximum velocity of the piston? (m/s) piston cylinder The frequency is the number of cycles (or revolutions) per second. Hence the frequency is 5400/60= Hz. Then use w=2nf to caculate the angular frequeny. x SHM

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What is the maximum accelaration of the piston? (m/s/s)
Answer: 76746
Use thew formala a=Aw² to calculate the maximum acceleration.
X
In SHM, where does the maximum acceleration occur?
Select one:
a. Middle (Equillibrium)
b. Top and Bottom (Extremes)
X
Transcribed Image Text:What is the maximum accelaration of the piston? (m/s/s) Answer: 76746 Use thew formala a=Aw² to calculate the maximum acceleration. X In SHM, where does the maximum acceleration occur? Select one: a. Middle (Equillibrium) b. Top and Bottom (Extremes) X
The piston inside a car cylinder osscilates up and down with Simple Harmonic Motion at
5400 cylces per minute. It travels upwards through a distance of 24cm and downwards
through 24cm each cycle.
What is the amplitude of the SHM? (m)
Answer: 0.24
X
What is the angular frequency of the motion? (rad/s)
Answer: 565.5
The total distance moved is 24cm. The equillibrium position is in the middle. Hence the amplitude is equal
to half of 24 cm, 0.12m.
x
Answer: 135.72
What is the maximum velocity of the piston? (m/s)
x
cylinder
piston
+
The frequency is the number of cycles (or revolutions) per second. Hence the frequency is 5400/60= Hz.
Then use w=2nf to caculate the angular frequeny.
Use the formula V=Aw to calculate maximum velocity.
SHM
Transcribed Image Text:The piston inside a car cylinder osscilates up and down with Simple Harmonic Motion at 5400 cylces per minute. It travels upwards through a distance of 24cm and downwards through 24cm each cycle. What is the amplitude of the SHM? (m) Answer: 0.24 X What is the angular frequency of the motion? (rad/s) Answer: 565.5 The total distance moved is 24cm. The equillibrium position is in the middle. Hence the amplitude is equal to half of 24 cm, 0.12m. x Answer: 135.72 What is the maximum velocity of the piston? (m/s) x cylinder piston + The frequency is the number of cycles (or revolutions) per second. Hence the frequency is 5400/60= Hz. Then use w=2nf to caculate the angular frequeny. Use the formula V=Aw to calculate maximum velocity. SHM
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What is the maximum accelaration of the piston? (m/s/s)
Answer: 76746
Use thew formala a=Aw² to calculate the maximum acceleration.
X
In SHM, where does the maximum acceleration occur?
Select one:
a. Middle (Equillibrium)
b. Top and Bottom (Extremes)
X
Transcribed Image Text:What is the maximum accelaration of the piston? (m/s/s) Answer: 76746 Use thew formala a=Aw² to calculate the maximum acceleration. X In SHM, where does the maximum acceleration occur? Select one: a. Middle (Equillibrium) b. Top and Bottom (Extremes) X
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