We are givenf = 0.685 Hz, d = 0.510 m, and m = 2.10 kg. We have the following equation for the period. %3D T= 2x V mgd This gives 4x21 72 = mgd %3D and, solving for the moment of inertia, we have the following. T?mgd I = 4x2 2 mgd %3D 4x2 kg (9.80 m/s?)( m) Hz kg m2

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The equations used to describe the physical pendulum will lead us directly to an answer.
Part 3 of 3 - Analyze
We are givenf = 0.685 Hz, d 0.510 m, and m = 2.10 kg. We have the following equation for the period.
T = 2n
V
mgd
This gives
4721
T2 =
mgd
and, solving for the moment of inertia, we have the following.
T?mgd
mgd
%3D
kg )(9.80 m/s?)
m
Hz
kg - m2
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Skip (you cannot come back)
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Transcribed Image Text:The equations used to describe the physical pendulum will lead us directly to an answer. Part 3 of 3 - Analyze We are givenf = 0.685 Hz, d 0.510 m, and m = 2.10 kg. We have the following equation for the period. T = 2n V mgd This gives 4721 T2 = mgd and, solving for the moment of inertia, we have the following. T?mgd mgd %3D kg )(9.80 m/s?) m Hz kg - m2 Submit Skip (you cannot come back) Need Help? Read it O Show My Work (Optional) ?
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