In an experiment of moment of inertia and angular acceleration, the experimental moment o inertia (I-experimental) and theoretical moment of inertia (I,-theoricai) are found as 8.75 x 10-3 kgm2 and 8.25 x 10-3 kgm2, respectively. Find the % error,
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- (a) Convert 34.0° to radians, using the appropriate conversion ratio. rad (b) Convert 2.32 rad to degrees. (c) If a circle has radius 1.10 m, what is the arc length subtended by a 34.0° angle? Submit AnswerNeeds Complete typed solution with 100 % accuracy.Answer the question in full details, thank you very much: A uniform, solid 2.5 kg cylinder can rotate about an axis through its center at O. The forces applied are : F1 =45N, F2 =4.3N, F3 = 5.5N,and F4 = 4.8 N. Also, R1 = 10. cmand R3 = 4.2cm. Find the magnitude (in rad/s^2) and direction (+ denotes counterclockwise and — denotes clockwise) of theangular acceleration of the cylinder.
- A person pushes on a lever 0.7 meters away from the axis of rotation with 100 N of force. The rotational inertia of the lever is 35 kg*m2. Calculate the angular acceleration of the lever.The moment of inertia for a set of objects of mass m; rotating about a common axis is defined as 1 = Σm₁r? 2 where r, is the distance of the ith object to the axis of rotation. If there are many particles that make up a larger object then this sum transforms into an integral, 4-fff or a. I = dV, V where p is the mass density and V the volume of the object. In this exercise we will explore moment of inertia by rolling two objects down an incline plane in the Experimental Math Lab Space.Suppose you exert a force of 172 N tangential to a 0.295 m radius 75.0 kg grindstone (a solid disk). (Give your answers to at least 2 decimal places.) (a) What torque (in N · m) is exerted? (Enter the magnitude.) N. m (b) What is the angular acceleration (in rad/s2) assuming negligible opposing friction? (Enter the magnitude.) |rad/s? (c) What is the angular acceleration (in rad/s?) if there is an opposing frictional force of 22.6 N exerted 1.75 cm from the axis? (Enter the magnitude.) |rad/s?
- Torque can be calculated by multiplying the force (NN90∘90∘ to the lever arm at a distance (mm) from the pivot point (point of rotation), the compound SI unit for the torque is N⋅mN⋅m. If the force (at 90∘90∘ to the lever arm) applied is 15 N15 N and it is applied at 2.0 m2.0 m from the pivot point (point of rotation), what is the torque on the lever?Suppose you exert a force of 172 N tangential to a 0.295 m radius 75.0 kg grindstone (a solid disk). (Give your answers to at least 2 decimal places.) (a) What torque (in N · m) is exerted? (Enter the magnitude.) 50.74 N. m (b) What is the angular acceleration (in rad/s?) assuming negligible opposing friction? (Enter the magnitude.) 15.55 rad/s? (c) What is the angular acceleration (in rad/s?) if there is an opposing frictional force of 22.6 N exerted 1.75 cm from the axis? (Enter the magnitude.) 15.44 ]× rad/s²To study torque experimentally, you apply a force to a beam. One end of the beam is attached to a pivot that allows the beam to rotate freely. The pivot is taken as the origin or your coordinate system. You apply a force of F = Fx i + Fy j + Fz k at a point r = rx i + ry j + rz k on the beam. 1. Enter a vector expression for the resulting torque, in terms of the unit vectors i, j, k and the components of F and r. 2. Calculate the magnitude of the torque, in newton meters, when the components of the position and force vectors have the values rx = 3.03 m, ry = 0.035 m, rz = 0.085 m, Fx = 2.8 N, Fy = 4.8 N, Fz = 5.8 N. 3. If the moment of inertia of the beam with respect to the pivot is I = 71 kg˙m2, calculate the magnitude of the angular acceleration of the beam about the pivot, in radians per second squared.
- Suppose you exert a force of 192 N tangential to a 0.255 m radius 75.0 kg grindstone (a solid disk). (Give your answers to at least 2 decimal places.) (a)What torque (in N · m) is exerted? (Enter the magnitude.) (b) What is the angular acceleration (in rad/s2) assuming negligible opposing friction? (Enter the magnitude.) (c) What is the angular acceleration (in rad/s2) if there is an opposing frictional force of 21.6 N exerted 2.50 cm from the axis? (Enter the magnitude.)Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. The moment of inertia of a disk about its center is I = (1/2)MR². (a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and passing through its center? (b) What is the angular acceleration of the disk? 11.9 N 0.350 m 40.0° 14.6 N 8.50 NNeeds Complete typed solution with 100 % accuracy.