In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.2 and a standard deviation of 15.3. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with…
A: From the provided information, Sample size (n) = 64 Sample mean (x̅) = 0.9 Sample standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with…
A: The mean is 4.7 and standard deviation is 17.1.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: Given, Sample size = 42 Sample mean = 4.9 Sample standard deviation = 16.6
Q: In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with…
A: Obtain the 99% confidence interval estimate of the mean net change in LDL cholesterol after the…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A: Given : The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with…
A: (1). Null and alternate hypotheses: The investigator is specifically interested to test whether the…
Q: garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus…
A: From the provided information, Sample size (n) = 81 Sample mean (x̅) = 0.9 Sample standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with…
A: The following information is provided: Mean difference xd=0.3 Standard deviation sd=2.36…
Q: the test of the effectiveness of garlic for lowering cholesterol. 49 subjects were treated with…
A: Given Data : Sample Size, n = 49.0 Sample Mean, x̄ = 4.4 standard…
Q: Answer: What is the null distribution of the test statistic? Select one O a. AT distribution with 35…
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Q: In a test of the effectiveness of garlic for lowering cholesterol,64 subjects were treated with raw…
A: Given: n = 64 d = 0.7 sd = 1.51 α = 0.01 Formula Used: Test-statistic-t = d-μdsdn
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: given data sample size (n) = 42sample mean ( xd¯ ) = 5.5sample standard deviation (sd) =17.490% ci…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: Sample size, Sample mean, Sample standard deviation, The confidence level is 0.90.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw…
A: Given Information: Sample size (n) = 36 Sample mean (x¯) = 0.7 Standard deviation (s) = 1.95…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with…
A: Solution: Let d be the difference between before and after. From the given information, d-bar=5.5,…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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Q: confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment.…
A: From the provided information, Sample mean (x̄ d ) = 4.4 Sample size (n) = 50 standard deviation (s…
Q: in a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: From the provided information, Sample size (n) = 50 Sample mean (x̄) = 3.7 Sample standard deviation…
Q: n LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the…
A: The mean change (before - after) is 5.8 SD of change is 19.6 Sample size n = 50 then the degrees of…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: The degrees of freedom is, df=n-1=44-1=43 The critical-value is obtained by using Excel function…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with…
A: We have given thatMean(µ) = 0Sample size (n) = 36Sample mean (x̅) = 0.7Standard deviations (s) =…
Q: for lowering cholesterol,45 subjects were treated with garlic in a processed tablet form.…
A: Given Data : Sample Size, n = 45 Sample Mean, x̄ = 5.1 sample standard…
Q: In a test of the effectiveness of garlic for lowering cholesterol,43 subjects were treated with…
A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A: Given Information: Sample size n=49 Mean of the differences d¯=0.3 (sample mean) Standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: We have given that Mean = 3.3, sample size n = 44 standard deviation s = 18.4 significance level =…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with raw…
A: Given information: Number of subjects used for test of the effectiveness of garlic n=36 The mean of…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: Given that: Sample size, n=44 Sample mean, x¯=4.4 Standard deviation, s=19.4 Confidence level is…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: It is given that sample mean is 4.4 and the standard deviation is 19.3.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
A: It is given that sample mean is 2.7 and standard deviation is 18.9.
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
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Q: na test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 36 subjects were treated with…
A: Given information- Sample size, n = 36 Significance level, α = 0.10 Sample mean, d-bar = 0.6 Sample…
Q: veness of ganic Construct a 99% confidence interval estimate of the mean net change in LDL…
A: Given,sample size(n)=42sample mean(x¯)=4.1standard deviation(s)=19.1degrees of…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 36subjects were treated with raw…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with…
A: From the provided information, Sample size (n) = 50 Sample mean (x̅) = 5.8 Sample standard deviation…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with…
A: From the provided information, Sample size (n) = 44 Sample mean (x̄) = 5.7 mg/dL Standard deviation…
Q: a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A:
In a test of the effectiveness of garlic for lowering cholesterol,
subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes
in their levels of LDL cholesterol (in mg/dL) have a mean of
and a standard deviation of
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- In a test of the effectiveness of garlic for lowering cholesterol, 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.9 and a standard deviation of 20.8. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. .... What are the null and alternative hypotheses? O B. Ho: H= 0 mg/dL O A. Ho: u= 0 mg/dL H,: µ0 mg/dL H1: µ> 0 mg/dL H,: µ<0 mg/dL Determine the test statistic. 0.39 (Round to two decimal places as needed.) Determine the P-value (Round to three decimal places as needed.)In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.2 and a standard deviation of 1.81. Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H>0 mg/dL O B. Ho: H=0 mg/dL H:H0 mg/dL Determine the test statistic. (Round to two decimal places as needed.)In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.7 and a standard deviation of 17.8. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?
- In a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (beforeafter) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.8 and a standard deviation of 19.2. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?In a test of the effectiveness of garlic for lowering cholesterol, 44 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.6 and a standard deviation of 17.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? Omg/dLIn a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.3 and a standard deviation of 16.4. Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.4 and a standard deviation of 16.7. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL <µ< mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? A. The confidence interval limits contain 0, suggesting that the…In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.2 and a standard deviation of 19.3. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean μ? ___mg/dL<μ<____mg/dL (Round to two decimal places as neededIn a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 20.7. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. Ho: μ = 0 mg/dL H₁: μ> 0 mg/dL C. Ho: μ = 0 mg/dL H₁: μ#0 mg/dL Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the…In a test of the effectiveness of garlic for lowering cholesterol, 42 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 4.1 and a standard deviation of 19.1. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? mg/dL < µIn a test of the effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before−after)in their levels of LDL cholesterol (in mg/dL) have a mean of 4.6 and a standard deviation of 16.3. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? What is the confidence interval estimate of the population mean μ? ______ mg/dL<μ<_____ mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? A. The confidence interval limits contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels. B. The confidence interval limits contain 0, suggesting that the garlic treatment…In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 1.92. Use a 0.05 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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