In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterollevels were measured before and after the treatment. The changes (before minus after) in their levels of LDLcholesterol (in mg/dL) have a mean of 0.6 and a standard deviation of 20.7. Use a 0.05 significance level to test theclaim that with garlic treatment, the mean change in LDL cholesterol is greater than 0. What do the results suggestabout the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify thenull and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.What are the null and alternative hypotheses?A. Ho: μ = 0 mg/dLH₁: μ> 0 mg/dLC. Ho: μ = 0 mg/dLH₁: μ#0 mg/dLDetermine the test statistic.(Round to two decimal places as needed.)Determine the P-value.(Round to three decimal places as needed.)State the final conclusion that addresses the original claim.Ho. There is▼0.B. Ho: μ> 0 mg/dLH₁: μ<0 mg/dLD. Ho: μ = 0 mg/dLH₁: μ<0 mg/dLevidence to conclude that the mean of the population of changes

Solution-: Given: sd=20.7,d¯=0.6,n=49,μd=0,α=0.05 We want to (a) Identify the null and alternative…

Answered: In a test of the effectiveness of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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15
Low-density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the arteries. This is why LDL is known as "bad cholesterol." LDL is measured in milligrams per deciliter of blood, or mg/dL. In a population of adults at risk for cardiovascular problems, the distribution of LDL levels is normal, with a mean of 123 mg/dL and a standard deviation of 41 mg/dL. If an individual's LDL is at least 1 standard deviation or more above the mean, he or she will be monitored carefully by a doctor. What percentage of individuals from this population will have LDL levels 1 or more standard deviations above the mean? Use the 68–95–99.7 rule. (Enter your exact answer as a whole number.) percentage %
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